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kotykmax [81]
3 years ago
13

Stuck on this one, help asap please

Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0

Answer:

Tan B = 24/10 = 12/5

Step-by-step explanation:

Tangent is opposite/adjacent. The side opposite of B is 24 and adjacent to that is 10.

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Charlie's weight is nine kilograms greater than his brother's. Together they weigh 99 kilograms. Let x represent the weight of t
siniylev [52]


If the weight of the little brother is x, then the weight of  Charles is x + 9

The equation that can be used to determine what each one weighs is:

x + (x + 9) = 99.

Let us now solve it.

x + x +9 = 99

2x + 9 = 99

2x = 99 - 9

2x = 90

x = 90/2

x = 45

Little brother's  weight is 45 kg.

Charles'   weight  will be 45 + 9 =  54 kg

Adding these two weights will give 99kg

 

4 0
3 years ago
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(Need help ASAP!) Select the equation that most accurately depicts the word problem.
antiseptic1488 [7]
I the answer is C I’m not really sure but I’ll update u when i get the answer
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Suppose that 20% of students at high school A and 18% of students at high school B participate on a school athletic team. Indepe
daser333 [38]

Answer:

let me answer this and i will come back

Step-by-step explanation:

7 0
3 years ago
If Qr=58 and pq=13 find pr
Oksanka [162]

Answer:

PR=71

Step-by-step explanation:

visualize:

P                Q               R

O-------------O-------------O

       13               58

so if PQ + QR = PR, than 13+58=PR

13+58=71

PR=71

6 0
3 years ago
I just need the inequality/equation please!
vladimir2022 [97]

Let x represent the amount that she needs to save each month for the next year.

Stephanie is saving money to buy a new computer. So far she has saved $200. This means that the total amount that she would have saved in y months is

200 + xy

Since there are 12 months in a year,

an inequality to show how much she needs to save each month for the next year so she has at least $1200 to spend on the computer is

200 + 12x ≥ 1200

12x ≥ 1200 - 200

12x ≥ 1000

x ≥ 1000/12

x ≥ 83.33

4 0
3 years ago
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