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uysha [10]
3 years ago
6

In the graphic below, ARV = ENV by:

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0
The ans should be ASA because angle AVR is equal to angle EVN (opposite angles equal) 
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A scatter plot is made comparing x, the number of hours since midnight, with y, the number of lights turned on in a house. What
Zepler [3.9K]

Answer:

7 hours since midnight and 8 lights turned on.

Step-by-step explanation:

(x,y) so 7 is the x and 8 is the y.

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2 years ago
An article written for a magazine claims that 78% of the magazine's subscribers report eating healthily the previous day. Suppos
Schach [20]

Answer:

89.44% probability that less than 80% of the sample would report eating healthily the previous day

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.78, n = 675

So

\mu = E(X) = np = 675*0.78 = 526.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{675*0.78*0.22} = 10.76

What is the approximate probability that less than 80% of the sample would report eating healthily the previous day?

This is the pvalue of Z when X = 0.8*675 = 540. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{540 - 526.5}{10.76}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

89.44% probability that less than 80% of the sample would report eating healthily the previous day

8 0
3 years ago
If y=4 when x=16, find y when x=6
timurjin [86]
The answer is 2 I think
6 0
3 years ago
I will mark brainlest
vodka [1.7K]

20 Square units jit. now give me brainliest.

3 0
2 years ago
Mr. Johns has up to 100 ceramic goods including mugs and plates available for his art class to decorate at the end of the year.
MA_775_DIABLO [31]

Answer:

m + p >= 100

m >= 40

p >= 10

Step-by-step explanation:

let m = number of mugs

let p = number of plates

4 0
3 years ago
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