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dlinn [17]
4 years ago
9

Please help asap 25 pts

Mathematics
1 answer:
yuradex [85]4 years ago
6 0

Since y has to be larger, the area is above the line.

Since the boundary is included (because of ≥ in stead of >) it should be drawn as a solid line.

Brings us to answer A, right?

See plot below.

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Solve the system of equations given by 5x - 2y = -6 and 15x - 6y = 6
AURORKA [14]

Answer:

8x - 3y = 12 _______( 1 )

5x = 2y + 7 _______( 2 )

On further solving ( 2 ), we get

5x - 2y = 7 _______( 3 )

Multiply ( 1 ) by 2

16x - 6y = 24 _______( 4 )

Multiply ( 3 ) by 3

15x - 6y = 21 _________( 5 )

Subtract ( 4 ) and ( 5 )

( 16x - 6y ) - ( 15x - 6y ) = 24 - 21

16x - 6y - 15x + 6y = 3

Put this in ( 2 )

5 ( 3 ) = 2y + 7

15 = 2y + 7

2y = 15 - 7

2y = 8

y = 8 / 2

Step-by-step explanation:

8 0
4 years ago
Katie invested a total of ​$4000​, part at 2​% simple interest and part at 3​% simple interest. At the end of 1​ year, the inves
Fiesta28 [93]

Answer:

$3000

$1000

Step-by-step explanation:

the formula for simple interest = principal x time x interest rate

let the amount invested in the 2% investment be a

let the amount invested in the 3% investment be (4000 - a)

(a x 0.02 x 1) + ([4000 - a] x 0.03 x 1) = $90

0.02a + 120 - 0.03a = 90

Collect like terms and solve for a

0.01a = 30

a = $3000

The amount invested in the 3% investment be (4000 - a)  = $4000 - $3000 = $1000

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A<br> .<br> b.<br> 2.<br> L<br> 37°<br> B<br> LABD =<br> LHFG =<br> d.
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What in the hell is this
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the location of a post office is marked at (2,2) on a coordinate grid. which point is about 18 units from the location of the po
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3 years ago
An alloy is composed of nickel, zinc, and copper in a ration of 7:2:9. How many kilograms of each metal are needed to make 3.6kg
motikmotik
Well, the short answer is, we divide that 3.6 by (7+2+9) and then we give as many pieces at the ratio to each, so let's do so,

\bf \stackrel{nickel}{7}~~:~~\stackrel{zinc}{2}~~:~~\stackrel{copper}{9}&#10;\\\\\\&#10;\stackrel{nickel}{7\cdot \frac{3.6}{7+2+9}}~~:~~\stackrel{zinc}{2\cdot \frac{3.6}{7+2+9}}~~:~~\stackrel{copper}{9\cdot \frac{3.6}{7+2+9}}&#10;\\\\\\&#10;\stackrel{nickel}{7\cdot 0.2}~~:~~\stackrel{zinc}{2\cdot 0.2}~~:~~\stackrel{copper}{9\cdot 0.2}&#10;\\\\\\&#10;\stackrel{nickel}{1.4}~~:~~\stackrel{zinc}{0.4}~~:~~\stackrel{copper}{1.8}
6 0
3 years ago
Read 2 more answers
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