Ask question

Ask question

All categories

VashaNatasha [74]

2 years ago

12

Circle O has a diameter of length 16. A point is located outside of the circle such that it lies 12 units from the circle's cent

er. What would the length of a segment drawn from tangent to circle beExpress your answer in simplest radical form.

1 answer:

olga2289 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

radius=16/2=8 units

d=12 cm

reqd. length=√(12²-8²)=√(144-64)=√80=4√5 units

You might be interested in

Find an equation for the nth term in the following sequence:<br> 2, 8, 32, 128, 512...

seraphim [82]

Answer:

$a_n = 2(4) ^{n-1}$

Step-by-step explanation:

The sequence shown matches that of a geometric sequence of radius 4. To prove it, divide the term $\frac{a_{n + 1}}{a_n}$ and check that $\frac{a_{n + 1}}{a_n}=4$

Then the formula that represents this sequence is:

$a_n = a_1(r)^{n-1}$

Where $a_1$ is the first term of the series = 2 and $r$ is the radius of convergence = 4.

Then the equation is:

$a_n = 2(4) ^{n-1}$

8 0

2 years ago

Read 2 more answers

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

7 0

2 years ago

Read 2 more answers

I WILL GIVE 44 POINT PLEASE HELP!!!!!

Nina [5.8K]

$|\Omega|=50\\ |A|=26\\\\ P(A)=\dfrac{26}{50}$

8 0

2 years ago

Read 2 more answers

Which line is parallel to the line 8x + 2y = 12?<br> 19

Katen [24]

Answer:

4x + y =6

Step-by-step explanation:

Line 8x + 2y = 12 is parallel to the line 4x + y = 6.

7 0

3 years ago

Pls help<br> Find the volume of the composite solid.

BaLLatris [955]

6cm this should be right

4 0

2 years ago