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Volgvan
4 years ago
14

Pls help

Mathematics
2 answers:
amid [387]4 years ago
7 0

Answer: maxium force = 785.2

Step-by-step explanation:

1.6m lower bound = 1.55

2.3m lower bound = 2.25

lower bound area = 1.55×2.25=3.4875

lower upper bound = 1.65×2.35=3.8775

pressure upper bound=202.5

pressure lower bound=197.5

202.5×3.8775=785.19375

197.5×3.4875=688.78125

force upper bound = 785.2

force lower bound = 688.8

gets you full marks

sineoko [7]4 years ago
4 0

Step-by-step explanation:

Force = pressure * area

= 200 * 3.7

= 740 N

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Bruce bought a map that cost $7.35 he used a $10 bill to pay for his map what is the change
ankoles [38]
$2.65

You can get this by subtracting the 7.35 from the 10. 

10 - 7.35 = 2.65
3 0
3 years ago
Can someone help me with this please....ill give points and brainless​
den301095 [7]

Answer:

The total surface area of the given cone is

S = 4( \sqrt{3}+1)\pi  cm^2

Step-by-step explanation:

<u>Step 1</u>:-

<u>Formula:-</u>

The total surface area of cone is

S.A = \pi r l +B

S.A = \pi r l +area of base

S.A = \pi r l+ \pi r^2........(1)

<u>Step 2:-</u>

Given slant height l = 2\sqrt{3} cm

and radius of the circle (base) = 2

substituting these values in equation (1)

S.A = \pi (2)(2\sqrt{3} ) + \pi (4)

on simplification, we get

S.A = \pi (4\sqrt{3}+4)

<u>Final answer</u> :-

S.A = 4 (\sqrt{3}+1)\pi cm^2

8 0
3 years ago
1. Latoya baked b cookies, her family ate 13 of them. Using b write an expression for the number of cookies that remained :)
fiasKO [112]

Answer:

b-13

Step-by-step explanation:

I'm pretty sure this is right? Unless I'm missing something, if I am I am terribly sorry.

5 0
3 years ago
Read 2 more answers
Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
3 years ago
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Without computing, decide whether the value of each expression is much smaller than one, closer to one, or much greater than one
d1i1m1o1n [39]

Answer:

C: closer to one

D: much smaller than one

E: much greater than one

F: much smaller than one

Step-by-step explanation:

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