Question

If the equation of a circle is (x - 2)2 + (y-6)2 = 4, it passes through point

Answer 1

(x - 2)² + (y - 6)² = 4

You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point

Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)

So alternative b.

To be more certain just subs the point in the x and y, if its equal, it pass through

(x - 2)² + (y - 6)² = 4

To point (4, 6)

(4 - 2)² + (6 - 6)² = 4

(2²) + 0² = 4

4 = 4

Thats right