Answer:
i think its
Step-by-step explanation:
D
Answer:
The answer is 672.
Step-by-step explanation:
To solve this problem, first let's find the surface area of the rectangular prism. To do that, multiply each dimension with each (times 2 | just in case you don't understand [what I'm talking about is down below]).
8 x 8 x 2 = 128
8 x 11 x 2 = 176
8 x 11 x 2 = 176
Then, add of the products together to find the surface area of the rectangular prism.
176 + 176 + 128 = 480
Now, let's find the surface area of the square pyramid. Now, for this particular pyramid, let's deal with the triangles first, then the square. Like we did with the rectangular prism above, multiply each dimension with each other (but dividing the product by 2 | in case you don't understand [what i'm talking about is down below]).
8 x 8 = 64.
64 ÷ 2 = 32.
SInce there are 4 triangles, multiply the quotient by 4 to find the surface area of the total number of triangles (what i'm talking about is down below).
32 x 4 = 128.
Now, let's tackle the square. All you have to do is find the area of the square.
8 x 8 = 64.
To find the surface area of the total square pyramid, add both surface areas.
128 + 64 = 192.
Finally, add both surface areas of the two 3-D shapes to find the surface area of the composite figure.
192 + 480 = 672.
Therefore, 672 is the answer.
Answer:
C. June 28, 1776
Step-by-step explanation:
Submitting the Declaration of Independence to the Continental Congress, June 28, 1776. This image is considered one of the most realistic renditions of this historical event.
Answer:
6*$10= $60
4*$10=$40
60+40= $100
$100
Step-by-step explanation:
Answer: 1) 0.10
2) 0.60
3) 0.20
4) 0.10
<u>Step-by-step explanation:</u>
The total frequency is 20+120+40+20 = 200. This means they ran the experiment 200 times. The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):
![\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 200}&\underline{\text{Probability Distribution}}\\1&20&20\div200=&0.10\\2&120&120\div 200=&0.60\\3&40&40\div 200=&0.20\\4&20&20\div 200=&0.10\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7C%7Clc%7D%5Cunderline%7Bx%7D%26%5Cunderline%7Bf%7D%26%5Cunderline%7Bf%5Cdiv%20200%7D%26%5Cunderline%7B%5Ctext%7BProbability%20Distribution%7D%7D%5C%5C1%2620%2620%5Cdiv200%3D%260.10%5C%5C2%26120%26120%5Cdiv%20200%3D%260.60%5C%5C3%2640%2640%5Cdiv%20200%3D%260.20%5C%5C4%2620%2620%5Cdiv%20200%3D%260.10%5Cend%7Barray%7D%5Cright%5D)
