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vlabodo [156]
3 years ago
5

Mr. Kazadi said that in his 2nd-period class, 23 out of 25 students passed the test. What percent of the students passed the tes

t?
%
Mathematics
2 answers:
nasty-shy [4]3 years ago
8 0

\text{Hello there!}

To find a percentage, you will need to divide both numbers by each other. In this case, it would look similar to this:

\text{23 / 25 = ???}

Once you divide the two numbers, you should end up with a result of 0.92

Now, we are going to <u>move the decimal two spaces to the right</u> to end up with the result:

\text{092.}

Now, we are going to <u>remove the </u>0 as it is no longer required. Next, <u>add a percentage symbol to the last number</u>, and <u>remove the decimal from the number</u>.

Now, you should end up with something like this:

92\%

\fbox{So your final answer is going to be 92\%}

\rule{299}{1.5}

VikaD [51]3 years ago
7 0
The answer 92% of students passed the test.
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1. $48

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Step-by-step explanation:

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To find the sale price, you find out how much is the percentage of the original price. Example :

(20/100)/60 = $12

So $12 is the discount

thus sales price will be $60-$12=$48

Same thing for no.2, find the amount of the percentage and subtract it from the original price

For 3 and 4

To find the original price

1. Subtract the percentage from 100%

2. Multiply the sales price by 100

3. Divide the ans from no.2 by ans from no.1

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100%-40%=60%

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Hope this helps haha

5 0
3 years ago
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Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0
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So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: x^4+9x^2-4x^2-36

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: x^2(x^2+9)-4(x^2+9)

Now you can rewrite this as (x^2-4)(x^2+9) , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is a^2-b^2=(a+b)(a-b) . Applying that here, we have (x+2)(x-2)(x^2+9) . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 2x^2+10x-x-5

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 2x(x+5)-1(x+5)

Now you can rewrite the equation as (2x-1)(x+5) . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is (x+2)(x-2)(x^2+9)(2x-1)(x+5)=0</u></h3>
5 0
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