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vlabodo [156]
3 years ago
5

Mr. Kazadi said that in his 2nd-period class, 23 out of 25 students passed the test. What percent of the students passed the tes

t?
%
Mathematics
2 answers:
nasty-shy [4]3 years ago
8 0

\text{Hello there!}

To find a percentage, you will need to divide both numbers by each other. In this case, it would look similar to this:

\text{23 / 25 = ???}

Once you divide the two numbers, you should end up with a result of 0.92

Now, we are going to <u>move the decimal two spaces to the right</u> to end up with the result:

\text{092.}

Now, we are going to <u>remove the </u>0 as it is no longer required. Next, <u>add a percentage symbol to the last number</u>, and <u>remove the decimal from the number</u>.

Now, you should end up with something like this:

92\%

\fbox{So your final answer is going to be 92\%}

\rule{299}{1.5}

VikaD [51]3 years ago
7 0
The answer 92% of students passed the test.
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Step-by-step explanation:

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The distribution of \hat p is given by:

\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})

We want to find this probability:

P(\hat p>0.14)

And using the z score given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

Where:

\mu_{\hat p} = 0.12

\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149

If we find the z score for \hat p =0.14 we got:

z = \frac{0.14-0.12}{0.0149}= 1.340

So we want to find this probability:

P(z>1.340)

And using the complement rule and the normal standard distribution and excel we got:

P(Z>1.340) = 1-P(Z

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