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kow [346]
3 years ago
14

Accurately calculate the concentration of the diluted solution starting with the concentration of the stock fe(no3)3 solution (0

.2 m).
Chemistry
1 answer:
elena-s [515]3 years ago
8 0
Ans: 25 mM

For example, suppose we take the following concentrations:

Diluted Fe(NO_{3})_{3} =1 ml 

<span>1 M KSCN = 5 ml 
</span>
0.1 M HNO_{3}<span> = 2  ml 
</span>----------------------------------------
<span>Then, total volume = 8 ml 

Now, 
</span> <span>final concentration of  diluted Fe</span>(NO_{3})_{3}<span> =</span>\frac{Concentration - of Fe(NO_{3})_{3}*Volume of Fe(NO_{3})_{3}}{Total Volume} \\ \\<span> 
</span>
given stock solution is 0.2 M

Thus, concentration of diluted solution = \frac{0.2*1}{8} = 0.025 M = 25 milli M
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