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natulia [17]
2 years ago
5

Explain how the complexity and diversity of living things has changed over time

Chemistry
1 answer:
Oduvanchick [21]2 years ago
4 0

Answer:

Dylan invested $ 600 in a savings account at a 1.6 % annual interest rate . He made no deposits or withdrawals on the account for 2 years. The interest was compounded annually . Find, to the nearest cent, the balance in the account after 2 years. a₁ What information from the question is important ? b . How much does Dylan have in his bank account after 2 years ? Show work .

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Hi ,

Answer:

A chemical energy is changed to a electrical energy

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The Olympian swam 200 meters in 20 seconds. <br> 1) velocity<br> 2) acceleration<br> 3) speed
irakobra [83]

Answer: velocity

Explanation:

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BaCl2(aq) + Na2CO3(aq) BaCO3(s) + NaCl(aq
Vitek1552 [10]
This is the equation balanced:

<span>BaCl2(aq) + Na2CO3(aq) = BaCO3(s) + 2 NaCl(aq)

Then the coefficient in front of Na Cl is 2.

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</span>


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3 years ago
WILL GIVE BRANLIEST TO WHOEVER ANSWERS THIS QUESTION&gt;&gt;&gt; How many valence electrons does NaHCo3 have?
nydimaria [60]

Answer:

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Explanation:

5 0
3 years ago
What is the limiting reactant when 4 mol P4 and 4 mol S8 react.
In-s [12.5K]

Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

8 P₄ + 3 S₈ → 8 P₄S₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • P₄: 8 moles
  • S₈: 3 moles
  • P₄S₃: 8 moles

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?

moles of P_{4} =\frac{4 moles of S_{8} x8 moles of P_{4} }{3 moles of S_{8}}

<u><em>moles of P₄= 10.667 moles</em></u>

But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
2 years ago
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