Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Answer:
the answer is D I'm sure
Step-by-step explanation:
D
The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
Answer:
ksbdksvudkdbckx skxid SORRRYYYYY BUT I NEED POINTSSSSS :(
