Question

9. What is the tan(90-x)?

Answer 1

$\\ \sf\longmapsto tanx=\dfrac{Perpendicular}{Base}$

$\\ \sf\longmapsto tanx=\dfrac{4}{3}$

$\\ \sf\longmapsto x=tan^{-1}(4/3)$

$\\ \sf\longmapsto x=53°$

$\\ \sf\longmapsto tan(90-x)$

$\\ \sf\longmapsto cotx$

$\\ \sf\longmapsto cot53$

$\\ \sf\longmapsto \dfrac{3}{4}$

$\\ \sf\longmapsto 0.75$

Answer 2

Answer:

Since tan (90 ° -x) can be written as сot (x) (ie trigonometry formulas), knowing that the applied leg to the opposite one, then

assert that the answer is сot(x)=3/4=0.75

D.0.75