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Lera25 [3.4K]
2 years ago
12

9. What is the tan(90-x)?

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
6 0

\\ \sf\longmapsto tanx=\dfrac{Perpendicular}{Base}

\\ \sf\longmapsto tanx=\dfrac{4}{3}

\\ \sf\longmapsto x=tan^{-1}(4/3)

\\ \sf\longmapsto x=53°

\\ \sf\longmapsto tan(90-x)

\\ \sf\longmapsto cotx

\\ \sf\longmapsto cot53

\\ \sf\longmapsto \dfrac{3}{4}

\\ \sf\longmapsto 0.75

sesenic [268]2 years ago
5 0

Answer:

Since tan (90 ° -x) can be written as сot (x) (ie trigonometry formulas), knowing that the applied leg to the opposite one, then

assert that the answer is сot(x)=3/4=0.75

D.0.75

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A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h
Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0
3 years ago
Simplify each expression justify each step 6+(8x +13)
zhuklara [117]
That's easy you just need to listen in school to answer it
5 0
3 years ago
A 13foot lader i upagenst a tree the bottom of the ladder is 5 feet away form the tree how high is the ladder on the tree
SCORPION-xisa [38]

Think of the 13-ft length of the ladder as the hypotenuse of a right triangle. Represent the horiz. distance from foot of ladder to base of tree by x, or 5 ft.

Represent the vert. dist. from base of tree to top of ladder by y, which is unknown.


Then (13 ft)^2 = (5 ft)^2 + y^2, or


169 ft^2 = 25 ft^2 + y^2. This simplifies to y^2 = 144. Thus y = + 12 feeet.


Note: Please pay attention to your spelling: "lader i up agenst a tree" should be "the top of a 13-ft ladder is placed against a tree."

7 0
3 years ago
In a rational function, is the horizontal shift represented by the vertical asymptote?
ziro4ka [17]
<h3>Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>

A bit of further explanation:

The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.

Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h

For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.

7 0
3 years ago
Part A
olasank [31]
<h3>Answer:</h3>
  • B. f(x) = 3,000(0.85)^x
  • $1566.02
<h3>Step-by-step explanation:</h3>

Part A

At the end of the year, the value of the computer system is ...

... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)

... = 0.85 · (beginning value)

Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...

... f(x) = (beginning value) · 0.85^x

The beginning value is given as $3000, so this is ...

... f(x) = 3000·0.85^x

____

Part B

For x=4, this is ...

... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02

The value after 4 years is $1566.02.

8 0
3 years ago
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