A fourth degree polynomial equation is shown below.

1 answer:

6 0

4x^2-8x-12 =
(x -3) * (x +1)

4x^2-24x+32
(x -4) * (x -2)

Factored Form
(x -3) * (x +1) * (x -4) * (x -2) = 0

x = 3
x = -1
x = 4
x = 2

All four roots are real numbers and so the graph crosses the x-axis four times. The graph of the equation would resemble a "W".

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Temka [501]

The answer will be 141 adults

5 0

3 years ago

How much Zn and how much HCl should be used to produce 1.5 g ZnCl2

tatuchka [14]

Answer:

0.71963 g of Zn
0.80256 g of HCl

Step-by-step explanation:

The required mass of reactants can be computed from the number of moles of product.

moles of ZnCl₂ = (1.5 g)/(136.282 g) ≈ 0.0110066 moles

Then the mass of Zn required is ...

mass of Zn = (0.0110066 mol)(65.382 g/mol) = 0.71963 g

Two moles of HCl are used in the reaction with each mole of Zn, so the mass of HCl required is ...

mass of HCl = 2(0.0110066 mol)(36.458 g/mol) = 0.80256 g

_____

Comment

The discrepancy in the last two decimal places of the weights above versus the calculator output below comes from rounding of moles of Zn to 4 significant digits, instead of 5 or more. The number of moles of ZnCl₂ is closer to 0.0110066.