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2 years ago

10

the running back for the Bulldogs football team carried the ball nine times for a total loss of 15 3/4 yards find the average ch

ange in the field position on each run

1 answer:

Vitek1552 [10]2 years ago

6 0

The average change in the field position on each run is. -1 3/4

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Reciprocate 1 9/11 plz

s344n2d4d5 [400]

Answer:

11/20

Step-by-step explanation:

$\text{First, multiply 1 times 11, and then add the numerator. We have}\\\\\frac{1\cdot11+9}{11}=\frac{20}{11}\\\\\text{Then, reciprocal is just switching the numerator + denenomanator, so we have } \frac{11}{20}$

3 0

2 years ago

Which expressions are equivalent?

Hatshy [7]

Answer:

3(a-b) and 3a-3b. Equivalent

2a(2+b) and 4ab. Not equivalent

Step-by-step explanation:

hope this helps:)

6 0

2 years ago

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Which equation does the graph represent?

Art [367]

Answer:

It is the second answer

Step-by-step explanation:

The standard form of an ellipse is

x^2/a^2 + y^2/b^2 or x^2/b^2 + y^2/a^2 = 1

If the x is the main axis we use the first form. If the y is the main axis we use the second form. We will use the second form.

our a is 3 and our b is 4

x^2/3^2 + y^2/4^2

3 0

1 year ago

For the month of November in a certain city, 88% of the days are cloudy. Also in the month of November in the same city, 54%

Gnoma [55]

Answer:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

Step-by-step explanation:

We have these following probabilities:

An 88% probability that the day is cloudy.

An 54% probability that the day is both foggy and cloudy.

What is the probability that a randomly selected day in November will be foggy if it is cloudy?

This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

$P = \frac{0.54}{0.88} = 0.6136$

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

4 0

3 years ago

22 ft.<br> 5 ft.<br> 13 ft.\<br><br> i think you have to multiply im not sure

NemiM [27]

110 that's the answer I think

6 0

3 years ago

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