$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

$A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]$

$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

3 0

2 years ago

How many solutions does the following equation have? <br>-2z+10+7z=16z+7

BARSIC [14]

Make all a and constant number in different side
10-7=16z-7z+2z
3=11z
z=3/11

7 0

3 years ago

Read 2 more answers

If X is to 9 as eight is to 12 then x is equal to what'

Tems11 [23]

Answer:

X is 6.

Step-by-step explanation:

What we know:

There's a ratio between 8 and 12, which simplifies to 2/3.

So, to find what x is, just multiply 2/3 times 9, to get 6 as x.

4 0

3 years ago