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3 years ago

Consider the quadratic function:

Mathematics

1 answer:

MrRissso [65]3 years ago

8 0

Answer: the vertex would be (4,-25)

Step-by-step explanation:

id suggest using desmos. its an app/website and is super helpful.

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(62.1) x (3.2) = ?? Please help urgent!!!

Ivanshal [37]

Answer:

198.72

Step-by-step explanation:

if u remove the brakctes and multiplay both of them by 10 and then multiply (621x32=19872 then u divide it by 100 and u get the answer 198.72

5 0

3 years ago

PLEASE ANSWER IN SCIENTIFIC NOTATION WITH STEPS PLEASE DUE BY 10:15 AM NO BOTS

patriot [66]

Answer:

i think is c.

8 0

3 years ago

How many solutions does the equation 3x − 7 = 4 + 6 + 4x have? (5 points) Two None Infinitely many One

statuscvo [17]

Answer:

There is one solution.

x = -17

Proof and step-by-step explanation:

Step 1: Add the numbers

3x-7 = 4+6+4x

3x-7 = 10+4x

Step 2: Move terms

3x-7 = 10+4x

3x-4x = 10+7

Step 3: Collect the like terms and calculate the sum

3x-4x = 10+7

-x = 17

Step 4: Change the sign by multiplying both sides by -1

-x (×-1) = 17 (×-1)

x = -17

I hope this helped ! :)

7 0

4 years ago

Which of the following exerts gravity?

matrenka [14]

The answer is only planets, moons, and stars exerts gravity

6 0

3 years ago

The Turtle and Achilles compete. They start at the same time from the same place. Achilles runs at a speed of 13 mph while the T

grandymaker [24]

Answer:

2 minutes.

Step-by-step explanation:

Let t be the time taken in competition and the distance covered by Achilles be x miles.

We have been given that when Achilles reaches the finish line, the Turtle is 2/5 of a mile behind him. This means that distance covered by turtle will be: $x-\frac{2}{5}$ .

Achilles runs at a speed of 13 mph while the Turtle moves at a speed of 1 mph.

Since we know that $\text{Time}=\frac{\text{Distance}}{\text{Speed}}$ , so we can set two equations for time taken by Achilles and turtle as:

$t=\frac{x}{13}...(1)$

$t=\frac{(x-\frac{2}{5})}{1}...(2)$

From equation (1) we will get,

$x=13t$

Upon substituting this value in equation (2) we will get,

$t=\frac{13t-\frac{2}{5}}{1}$

Let us have a common denominator.

$t=\frac{\frac{65t-2}{5}}{1}$

$t=\frac{65t-2}{5}$

Upon multiplying both sides of our equation by 5 we will get,

$5t=5\times \frac{65t-2}{5}$

$5t=65t-2$

$5t-65t=65t-65t-2$

$-60t=-2$

$t=\frac{-2}{-60}$

$t=\frac{1}{30}$

So, the competition took 1/30 hour, let us convert our given time in minutes.

$\frac{1}{30}\text{ hour}\times \frac{60\text{ minutes}}{\text{hour}}$

$\frac{1}{30}\times 60\text{ minutes}$

$2\text{ minutes}$

Therefore, the competition took 2 minutes.

8 0

3 years ago