Answer:
s = 6, r = 8 or s = 4, r = 7
Step-by-step explanation:
2r - s = 10
2r = 10 + s
r = 5 + s/2 --(1)
rs - s^2 = 12 --(2)
sub (1) into (2):
(5 + s/2)s - s^2 = 12
5s + 0.5s^2 - s^2 = 12
-0.5s^2 + 5s - 12 = 0
s^2 - 10s + 24 = 0
(s - 6)(s - 4) = 0
therefore s = 6 or s = 4
when s = 6, r = 8 and when s = 4, r = 7
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Answer:
The third one. The square in the top left can only fold to the right or down.... which means there is guaranteed to be an open side remaining on the square.
Answer:
180 in
Step-by-step explanation:
10*6*3=180
Answer:
0 < t < 
After 1.67 days the stocks would be sold out.
Step-by-step explanation:
The price of a certain computer stock after t days is modeled by
p(t) = 100 + 20t - 6t²
Now we will take the derivative of the given function and equate it to zero to find the critical points,
p'(t) = 20 - 12t = 0
t = 
t = days
Therefore, there are two intervals in which the given function is defined
(0, ) and (, ∞)
For the interval (0, ),
p'(1) = 20 - 12(1) = 20
For the interval (, ∞),
p'(2) = 20 - 12(2) = -4
Positive value of p'(t) in the interval (0, ) indicates that the function is increasing.
0 < t <
Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.
Mulitply second equation by 2 and add to first
3y+2z=12
<u>2y-2z=18 +</u>
5y+0z=30
5y=30
divide 5
y=6
sub back
y-z=9
6-z=9
minus 6
-z=3
times -1
z=--3
x=-3
y=6
