Find the area of the shaded area
2 answers:
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The sketch of the garden and the pond is shown below
Area of garden = length × width
Area of garden = [3x + 5] × 3x
Area of garden = 3x[3x+5]
Area of garden = 9x² + 15x
Area of pond = [x-2] × x
Area of pond = x[x-2]
Area of pond = x² - 2x
Area to be re-sod = Area of garden - Area of pond
Area to be re-sod = 9x² + 15x - [x² - 2x]
Area to be re-sod = 9x² - x² + 15x + 2x
Area to be re-sod = 8x² + 17x
The amount of sod needed to be bought would depend on how much in each packaging they are being sold.
Area of garden = length × width
Area of garden = [3x + 5] × 3x
Area of garden = 3x[3x+5]
Area of garden = 9x² + 15x
Area of pond = [x-2] × x
Area of pond = x[x-2]
Area of pond = x² - 2x
Area to be re-sod = Area of garden - Area of pond
Area to be re-sod = 9x² + 15x - [x² - 2x]
Area to be re-sod = 9x² - x² + 15x + 2x
Area to be re-sod = 8x² + 17x
The amount of sod needed to be bought would depend on how much in each packaging they are being sold.
Answer:
The value of second quantity is 27
Step-by-step explanation:
Inverse variation can be represented by the equation xy=k or i.e,
y varies inversely as x , if there is some nonzero constant k such that, xy =k or where x≠0 and y≠0.
Given: Two quantities vary inversely.
Let x be the first quantity and y be the second quantity if they vary inversely.
then, by definition of inverse variation;
.....[1]
Substitute the value of x=15 and y=18 to solve for k;
Multiply both sides by 15 we have;
Simplify:
k=270
now, find the second quantity y using same method when x=10.
then;
after substituting the value of x=10 and k=270 in [1] ;
Simplify:
y= 27
Therefore, the second quantity value i.e,y = 27