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insens350 [35]
3 years ago
9

Help??? I Don’t Understand

Mathematics
1 answer:
Andrews [41]3 years ago
5 0
The correct answer is line TX and line QX are perpendicular.
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Solve the equation.<br> 9x=25
lidiya [134]

Answer:

x = \frac{25}{9}

Step-by-step explanation:

Divide both sides by 9 to isolate x:

\frac{9x}{9} = \frac{25}{9}  \\x = \frac{25}{9}\\

Hope this helps!

8 0
3 years ago
Solve the following equation for x: 5x + 3y = 15.
Blizzard [7]

Answer:

x = negative three fifthsy + 3

Step-by-step explanation:

5x + 3y = 15

Subtract 3y from both the sides,

5x = 15 - 3y

Divide by 5 on both sides,

x = -3y/5 + 15/5

x = -3y/5 + 3

7 0
3 years ago
Write the standard form of the equation of the circle that passes through the point
AnnZ [28]

Answer:

The standard form of the equation of the circle is x^2+y^2=1.

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

                                             (x-h)^2+(y-k)^2=r^2

where <em>r</em> is the radius of the circle,  and <em>h</em>, <em>k</em> are the coordinates of its center.

When the center of the circle coincides with the origin h=k=0, so

                                            (x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2

We are also told that the circle contains the point  (0, 1), so we will use that information to find the radius <em>r</em>.

                                                   0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}

Therefore, the standard form of the equation of the circle is x^2+y^2=1.

5 0
3 years ago
please help me The question involves multiplying two complex numbers, then turning it into an a+bi equation (pictures included)
Sloan [31]

Answer:

  (a, b) = (0, -15)

Step-by-step explanation:

In "cis" form the product of two complex numbers is the product of their magnitudes at the angle that is the sum of their angles. I find this the easiest way to multiply complex numbers.

  z1 × z2 = (3 cis π)(5 cis π/2)

  = (3·5) cis (π +π/2)

  = 15 cis 3π/2

Of course, "cis" is short for "cosine + i·sine", so you have ...

  z1 × z2 = 15 cis 3π/2 = 15(cos(3π/2) +i·sin(3π/2))

  = 15(0 +i·(-1))

  = 0 -15i

(a, b) = (0, -15)

8 0
3 years ago
Solve for x 9x + 1 equals 25 + x edg 2020?<br><br>x=2<br>x=3<br>x=4<br>x=5​
gregori [183]
No no no no no no no no no no no no
3 0
2 years ago
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