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Nat2105 [25]
3 years ago
13

Solve the system by substitution. y=6x y=3x+21 ( , )

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

(7,42)

Step-by-step explanation:

Imput the 6x for the Y:

6x=3x+21

move the variable to the left

6x-3x=21

collect like terms:

3x=21

divide both sides by 3x and youll get this for X

x=7

Imput x=7 into the equation

Y=6x7

solve:

y=42

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IgorLugansk [536]

Answer:

845.6306

Step-by-step explanation:

Firstly this is annuity based

Let, investment at beginning of year = <em>x</em>

Then value at year 1 end = x + (8.2% \times x)

Value at end of year 2 = (x + 0.082x) + (8.2% \times (x + 0.082x))

Now this value = $990

Therefore,

990 =  (x + 0.082x) + ((x + 0.082x) \times 8.2%)

990 = x + 0.082x + 0.082x + 0.006724x = 1.170724x

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3 0
3 years ago
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koban [17]

Answer:

y=4, x=8

Step-by-step explanation:

system:

x+y = 12, x=2y

convert to 1 variable, simplify:

2y+y=12

3y=12

y=4

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6 0
3 years ago
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Write two equelivant ratios 11 and 4​
timofeeve [1]

Answer:

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2 years ago
Can someone help me with this ?
LuckyWell [14K]

Answer:

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3 0
3 years ago
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drek231 [11]

Answer:

<h2>x + 2y = 8</h2>

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have:

y=-\dfrac{1}{2}x+4

Convert:

y=-\dfrac{1}{2}x+4            <em>multiply both sides by 2</em>

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