4 years ago

How can a translation and a reflection be used to map️HJK to ️LMN?

Mathematics

1 answer:

Fantom [35]4 years ago

8 0

Answer:Translate k to N and reflect across the line containing JK

Step-by-step explanation:

You might be interested in

HELP PLEASE!

navik [9.2K]

1.
20= 2(x-4)
20/2= 2(x-4)/2
10= x-4
+4 . +4
14=x

3 0

3 years ago

Read 2 more answers

Is 4 r square the answer...pls I need to know thank you :)

zloy xaker [14]

Step-by-step explanation:

$\pi {r}^{2} \\$

3 0

3 years ago

Someone please help!

igomit [66]

Answer:

-11/12 make sure you press the negative

8 0

3 years ago

Smplify the radical expression. How many different ways can you write your answer?

mel-nik [20]

Answer:

$2xy\sqrt[3]{2x^2z}$ and $2xy(2x^2z)^{\frac{1}{3}}$ .

Step-by-step explanation:

The given radical expression is

$\sqrt[3]{16x^5y^3z}$

We have to simplify the above expression.

The above expression can be written as

$\sqrt[3]{(2\times 8)(x^{3+2})y^3z}$

$\sqrt[3]{(2\times 2^3)(x^3\times x^2)y^3z}$ $[\because a^{m+n}=a^ma^n]$

$\sqrt[3]{(2^3x^3y^3)(2x^2z)}$

$\sqrt[3]{(2xy)^3}\sqrt[3]{2x^2z}$ $[\because (ab)^m=a^mb^m]$

$2xy\sqrt[3]{2x^2z}$ $[\because \sqrt[n]{x^n}=x]$

It can be written as exponent form.

$2xy(2x^2z)^{\frac{1}{3}}$ $[\because \sqrt[n]{a}=a^{\frac{1}{n}}]$

Therefore, the required expressions are $2xy\sqrt[3]{2x^2z}$ and $2xy(2x^2z)^{\frac{1}{3}}$ .

5 0

3 years ago

WILL MARK BRAINLIEST!

ankoles [38]

Answer:

Step-by-step explanation:

Both lines are not intersecting each other so that means they don't share a solution

8 0

3 years ago

How can a translation and a reflection be used to map️HJK to ️LMN?​

How can a translation and a reflection be used to map️HJK to ️LMN?