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SOVA2 [1]
2 years ago
10

Which statement is true about this equation? 3(-y 7) = 3(y 5) 6.

Mathematics
1 answer:
Ahat [919]2 years ago
8 0

The statement that is true about the equation 3(-y + 7) = 3(y + 5) + 6 is;

Statement A; The equation has one solution, y = 0

The given equation is;

3(-y + 7) = 3(y + 5) + 6

Expanding the brackets gives us;

-3y + 21 = 3y + 15 + 6

-3y + 21 = 3y + 21

Using subtraction property of equality, subtract 21 from both sides to give;

-3y = 3y

Using addition property of equality, add 3y to both sides to give;

-3y + 3y = 3y + 3y

6y = 0

Using division property of equality, divide both sides by 6 to get;

y = 0

Read more about factorization at; brainly.com/question/11000698

The missing statements are;

A. The equation has one solution, y = 0.

B. The equation has one solution, y = -1.

C. The equation has no solution.

D. The equation has infinitely many solutions.

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In the diagram, point X is the centroid. If<br> EX=8, what is the length of XC ?
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Answer:

16

Step-by-step explanation:

If X is the centroid that means that EC is a median along with the other lines that intersect inside the triangle. Medians drawn from a triangle have a special rule; this rule is that all medians have a 2:1 ratio between the different sections of one median. For example, EC is one median with the two sections XC and EX. Therefore XC and EX have a 2:1, with the 2 representing the longer section closest to the vertex. This means that XC is double EX, so to find XC simply double EX measurement, which is 8. So XC must equal 16.

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2 years ago
The sum of three numbers is 10. Two times the second number minus the first number is equal to 12.
eimsori [14]

<u>Answer:</u>

-10,1,19

<u>Step-by-step explanation:</u>

<u></u>

x+y+z = 10 (Equation 1)

2y-x= 12  (Equation 2)

x-y+2z = 7 (Equation 3)

(Equation 2): -x = -2y+12

                       x = 2y-12 (Equation 4)

(Equation 1) - (Equation 3): 2y-z = 3

                                              -z = -2y+3

                                               z = 2y-3 (Equation 5)

Substitute (4) and (5) into (1)

x+y+z = 10

(2y-12)+y+(2y-3) = 10

5y-15 = 10

5y = 5

y=1

Substitute y=1 into (2)

2y-x= 12

2(1)-x= 12

2-x= 12

-x= 12-2

-x= 10

x= -10

Substitute y=1 and x=-10 into (1)

x+y+z = 10

-10+1+z = 10

z-9 = 10

z = 10+9

z = 19

Order: x = -10, y = 1, and z = 19

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Answer:

B

Step-by-step explanation:

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6/9 and 12/21
i think this is the answer your looking for
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