Answer:

Step-by-step explanation:

Answer:
what are the options?
Step-by-step explanation:
It’s either volume or matter
Answer:
The distance between Harry’s home and his office? is 15 miles.
Step-by-step explanation:
The speed, distance time formula is:

Given:
Speed (<em>s</em>) = 30 miles/hour
Then the relation between distance and time is:

If Speed was 60 miles/hour the time taken is
hours.
Then the relation between distance and time is:

Use the value of <em>d</em> = 30t in (ii)
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Determine the distance as follows:

Thus, the distance between Harry’s home and his office? is 15 miles.
Trapezoid:
•Can have congruent diagonals. •Has one pair of opposite, parallel sides.
Kites:
•Has congruent adjacent sides.
•Has perpendicular diagonals.