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Sladkaya [172]
3 years ago
12

You use a ____ following the closing brace of an array initialization list.

Computers and Technology
2 answers:
Marysya12 [62]3 years ago
4 0

Answer:

a.

,

Explanation:

The array is used to store the multiple data with  same data type.

Syntax for initialization of array:

type name[] = {data_1, data_2, data_3,....};

the comma ',' is used to separate the data with other data.

for example:

int array[] = {1,2,3,4,5};

we cannot used dot '.', colon ':' and semicolon ';' as separator.

Sauron [17]3 years ago
4 0

Answer:

,

Explanation:

You use a , following the closing brace of an array initialization list.

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The answer would be 13.3125 because 6.25 / 0.8 is 7.8125 than add 5.5 which will equal 13.3125. I'm sure about this.
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What size hard disc is recommended for powerpoint writting
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3 years ago
I'm using assembly language. This is my assignment. I kinda confused about how to write code for this assignment. Can anyone exp
Brut [27]

Answer:

oid changeCase (char char_array[], int array_size ) {

__asm{

   mov eax, char_array;    

   mov edi, 0;

readArray:

   cmp edi, array_size;

   jge exit;

   mov ebx, edi;          

   shl ebx, 2;

   mov cl, [eax + ebx];    

check:

   //working on it

   cmp cl, 0x41;      

   jl next_indx;

   cmp cl, 0x7A;      

   jg next_indx;

   cmp cl, 'a';

   jl convert_down;

   jge convert_up;

convert_down:

   or cl, 0x20;        //make it lowercase

   jmp write;

convert_up:

   and cl, 0x20;      

   jmp write;

write:

   mov byte ptr [eax + ebx], cl    

next_indx:

   inc edi;

exit:

   cmp edi, array_size;

   jl readArray;

mov char_array, eax;

}

}

Explanation:

  • Move char_array to eax as it is base image .
  • Use ebx as offset .
  • Use ecx as the storage register .
  • check if cl is <= than ASCII value 65 (A) .
6 0
3 years ago
What are the values of the following expressions? In each line assume that,
MissTica

Answer:

double x = 2.5;

double y = -1.5;

int m = 18;

int n = 4;

string s = "Storm";

string t = "Watch";

The output of the expression "x + n*y - (x+n)*y" is "6.25".

and the output of expression "m/n + m%n" is "6".

Explanation:

for the first expression,

x + n*y - (x+n)*y ,put value of every variables in it.

=2.5+4*(-1.5)-(2.5+4)*(-1.5)

=2.5-6.0-(6.5*(-1.5)

=-3.5+9.75

=6.25

for the second expression,

m/n + m%n,  put value of every variables in it.

=18/4 +18%4

=4+2      ("/ will give quotient and % will give remainder")

=6

4 0
3 years ago
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