The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
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-1 1, -2 2, 3 -3. Is this what you wanted? If no tell me in comments and maybe a can help fix.
False, this statement is not true, because if you change the parenthesis, it means that you will do that thing first (PEMDAS)
Therefore, the sstatement is false, because the answers will be completely different,
hope this helps
Answer: Apply the Sum/Difference Rule
d/dx(7x)-d/dx(8)
d/dx(7x)=7
d/dx(8)=0
7-0=7
Step-by-step explanation: The answer is 7
1) The scale factor for the dilation is 2/3.
2) The polygon became smaller after the dilation because you are multiplying by a scale factor less than 1.
3) The ratio of the areas is 2/5.
