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3 years ago

I WILL GIVE BRAINLIEST!!!

Mathematics

1 answer:

adell [148]3 years ago

6 0

Answer:

2 by 4 by 678

Step-by-step explanation:

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The area of the rectangle below is greater than or equal to 18.13 square units. The inequality 3.7w ≥ 18.13 represents this

Katyanochek1 [597]

W>4.9 (NOTE: The greater than sign is supposed to be greater than OR equal to)

You can rewrite the inequality like this because you can simplify the equation to get rid of the 3.7. You do this by dividing both sides of the expression by 3.7, since that’s what the w is being multiplied by.

Hope this helps!

5 0

2 years ago

Three collinear points on the coordinate plane are r(x,y), s(x+8h, y+8k), and p (x+6h, y+6k)

Karo-lina-s [1.5K]

Answer:

A. $\frac{RP}{SP}=3$

B. $\frac{RP}{RS}=\frac{3}{4}$

Step-by-step explanation:

The complete question is

Three collinear points on the coordinate plane are R(x, y), S(x+8h, y+8k), and P(x+6h, y+6k).

Part A: Determine the value of RP/SP

Part B: Determine the value of RP/RS

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(x,y),S(x+8h,y+8k) and P(x+6h,y+6k)$

Part A.We have to find the value of $\frac{RP}{SP}$

step 1

Find the distance RP

$R(x,y),P(x+6h,y+6k)$

substitute the values in the formula

$RP=\sqrt{(x+6h-x)^2+(y+6k-y)^2}$

$RP=\sqrt{36h^2+36 k^2}$

$RP=6\sqrt{h^2+k^2}$

step 2

Find the distance SP

$S(x+8h,y+8k),P(x+6h,y+6k)$

substitute the values in the formula

$SP=\sqrt{(x+6h-x-8h)^2+(y+6k-y-8k)^2}$

$SP=\sqrt{4h^2+4k^2}$

$SP=\sqrt{4(h^2+k^2)}$

$SP=2\sqrt{h^2+k^2}$

step 3

Find the ratio RP/SP

$\frac{RP}{SP}=\frac{6\sqrt{h^2+k^2}}{2\sqrt{h^2+k^2}}$

$\frac{RP}{SP}=3$

Part B. We have to determine the value of $\frac{RP}{RS}$

step 1

Find the distance RS

$R(x,y),S(x+8h,y+8k)$

$RS=\sqrt{(x+8h-x)^2+(y+8k-y)^2}$

$RS=\sqrt{64h^2+64k^2}$

$RS=\sqrt{64(h^2+k^2)}$

$RS=8\sqrt{h^2+k^2}$

step 2

Find the ratio RP/RS

$\frac{RP}{RS}=\frac{6\sqrt{h^2+k^2}}{8\sqrt{h^2+k^2}}$

$\frac{RP}{RS}=\frac{3}{4}$

5 0

3 years ago

2. Squares are the only regular quadrilaterals. O True O False

Furkat [3]

Answer:

true

Step-by-step explanation:

The only regular (all sides equal and all angles equal) quadrilateral is a square. So all other quadrilaterals are irregular.

8 0

3 years ago

Read 2 more answers

Can someone please help me, i have a time limit, does anyone know the answer for number 6?!

jeka57 [31]

Answer:

36.7 I do believe Im not really sure though

6 0

3 years ago

Read 2 more answers

Find an equation of a line that pass through (4,3) and parallel to y=-4x+1

ivanzaharov [21]

Answer:

y = -4x + 19

Step-by-step explanation:

The line parallel to y = -4x + 1 would have the same slope of -4. The coefficient of x will be -4. We can put this into the equation y = -4x + a where a is the y-intercept and a ≠ 1. Now solve for a.

y = -4x + a

plug in 4 for x and 3 for y

3 = -4(4) + a

simplify

3 = -16 + a

+16 both sides

19 = a

a = 19

y = -4x + 19

3 0

3 years ago