The it takes to recognize a and your body responding to it. Blank 1: Blank 2:

How do you start the game of floor hockey

babunello [35]

Answer:

3

Explanation:

because it did=

4 0

3 years ago

A 20-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 26 n. starting from rest, the sle

Vesna [10]

Good morning.

We calculate the acceleration with the Torricelli equation:

$\star\ \boxed{\mathsf{V^2 = V_0^2 + 2a\Delta S}}$

We see that:

$\begin{cases}\mathsf{V_0 = 0}\\\mathsf{V = 2.3 \ m/s}\\\mathsf{\Delta S = 8.9 \ m}\end{cases}$

Now:

$\mathsf{(2.3)^2 = 0^2 + 2a\cdot 8.9}\\ \\ \mathsf{5.29 = 17.8a}\\ \\ \bold{\mathsf{a = 0.3 \ m/s^2}}$

Now we can calculate the resultant force that makes that acceleration of 0.3 m/s² with the 2nd Law of Newton:

$\mathsf{F_r = m\cdot a}\\ \\ \mathsf{F_r = 20\cdot 0.3}\\ \\ \mathsf{F_r = 6 \ N}$

We have a force of 26 N → and a friction force F ←. Adding those vectors, he have a force 6 N →. Therefore:

26 - F = 6

F = 20 N

We have a friction force of 20 N. We calculate the kinect coefficient with the formula:

$\star \ \boxed{\mathsf{F = \mu_k N}}$

Since we are in a horizontal plane, we hava that N = P = mg = 200 N

Therefore:

$\mathsf{20 = \mu_k 200}\\ \\ \boxed{\boxed{\mathsf{\mu_k = 0.1}}}$

5 0

4 years ago

Background Information: Energy can not be created or destroyed. Stored energy is called

Over [174]

Answer:

this question is very lengthy and even nit at all understandable so pls can u explain it in breif

5 0

3 years ago

What determines whether a real or a virtual image is formed from a concave mirror?

Gnesinka [82]

Answer:

The distance of the object from the concave mirror determines if it is a virtual or real image

Explanation:

Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.

4 0

3 years ago

An object in free fall near the surface of the earth accelerates at a rate of 78979.4 mi/hr What is the rate of acceleration for

Nina [5.8K]

Answer:

32.176 ft/s²

9.807 m/s²

Explanation:

Data provided in the question:

Acceleration of the free falling object = 78979.4 mi/hr²

a) In ft/s

Now,

1 mi = 5280 foot

and,

1 hour = 3600 seconds

thus,

78979.4 mi/hr = $\frac{\textup{78979.4}\times\textup{5280}}{\textup{1}\times\textup{3600}^2}$

or

78979.4 mi/hr = 32.176 ft/s² ...............(1)

b) In m/s²

Now,

1 foot = 0.3048 m

thus,

we have from 1

32.17 ft/s² = $\frac{\textup{32.17}\times\textup{0.3048}}{\textup{1}\times\textup{1}^2}$

or

78979.4 mi/hr = 32.176 ft/s² = 9.807 m/s²

7 0

3 years ago