Suppose the stone is thrown at an angle of 39.0° below the horizontal from the same building as in the Example above. If it strikes the ground 47.8 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)(a) the time of flight sThe x coordinate as a function of time is x(t) = vcos(39.0)t, so the initial speed is v0 = Δx/(cos 39.0Δt), where Δx = 47.8 and Δt is the time of flight. Insert this into your equation for y(t) and solve for the time of flight. Note that the answer should be smaller than 3.16227766016838, since the stone is thrown down (and to the right).(b) the initial speed m/s(c) the speed and angle of the velocity vector with respect to the horizontal at impactspeed m/sangle °
The answer is B) wavelength
Answer:
D
Explanation:
D it generates pressure by fusing hydrogen.
As we know that collision is elastic so we will have
also we can use momentum conservation
now from above two equations we will have
also we have
so both balls will separate after collision and move in opposite direction as the final velocities are opposite in sign
So correct answer will be
<em>D. The balls separate and move in opposite directions.</em>
neutral objects is correct
