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max2010maxim [7]
3 years ago
7

How much energy is needed to heat 55 Kg of water from 285 K to 360 K?

Physics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

17 kJ

Explanation:

q = mCΔT

q = (55 kg) (4.184 kJ/kg/K) (360 K − 285 K)

q = 17,000 J

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When another driver passes you on the left, you must _________ until the vehicle passes?
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A beaker is filled 60 cm high with this liquid. What is the total pressure at the bottom of the beaker? (1 atm =1.013 x 105 Pa)
Amiraneli [1.4K]

Answer:

Total pressure =1.01*10^5 Pa

Explanation:

given data:

atmospheric pressure = 1.013 *10^5 Pa\

height of water column = 60 cm

Total pressure will be sum of atmospheric pressure and pressure due to water column

P =  Atmospheric pressure + pressure due to water column

pressure due to water =\rho*g*h

\rho of water  = 1420 kg/m^{3}

height of water column = 60 cm =0.60 m

Total pressure =1.013*10^{5}Pa + 1420*9.81*.60

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Total pressure =1.01*10^5 Pa

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3 years ago
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6 0
3 years ago
a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal dista
ELEN [110]

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2}   (1)

Where:

x_{f}: is the final position in the horizontal direction = 80 m

x_{0}: is the initial position in the horizontal direction = 0

v_{0_{x}}: is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s

b) The height of the hill is given by:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final position in the vertical direction = 0

y_{0}: is the initial position in the vertical direction =?

v_{0_{y}}: is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m  

I hope it helps you!

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3 years ago
Help please, I don’t know the answer for this
Nikolay [14]

Answer:

d

Explanation:

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