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4 years ago

Fred buys flags from a manufacturer for (unknown) dollars each and then sells the flags in his store for a 26% markup

Mathematics

1 answer:

gtnhenbr [62]4 years ago

4 0

The answer is $50.40! hope this helps!

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How do I solve this question?

g100num [7]

Answer:

$-7 \frac{1}{2}$

Step-by-step explanation:

$\frac{6 {x}^{ - 1} {y}^{ \frac{7}{2} } }{ \sqrt{16 {x}^{2} } {y}^{2} } \\ \\ = \frac{6 {x}^{ - 1} {y}^{ \frac{7}{2} } }{ \sqrt{(4 {x} {y})^{2} }}\\ \\ = \frac{6 {x}^{ - 1} {y}^{ \frac{7}{2} } }{ {4 {x} {y}}}\\ \\ = \frac{6}{4} {x }^{ - 1 - 1} {y}^{ \frac{7}{2} - 1 } \\ \\ = \frac{3}{2} {x }^{ - 2} {y}^{ \frac{5}{2} } \\ \\ equating \: it \: with \: \\ a {x}^{b} {y}^{c} \\ \\ \implies \\ a = \frac{3}{2} \\ \\ b = - 2 \\ \\ c = \frac{5}{2} \\ \\ abc = \frac{3}{2} \times ( - 2) \times \frac{5}{2} \\ \\ = - \frac{15}{2} \\ \\ =- 7 \frac{1}{2} \\$

4 0

4 years ago

Please help!

BaLLatris [955]

a) The polynomial in expanded form is $f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ .

b) The slant asymptote is represented by the linear function is $y = -x + 1$ .

c) There is a discontinuity at $x = 2$ with a slant asymptote.

a) In this question we are going to use the Factor Theorem, which establishes that polynomial are the result of products of binomials of the form $x-r_{i}$ , where $r_{i}$ is the i-th root of the polynomial and the grade is equal to the quantity of roots. Therefore, the polynomial $f(x)$ has the following form:

$f(x) = (x-6)\cdot (x+1)\cdot (x+3)$

And the expanded form is obtained by some algebraic handling:

$f(x) = (x-6)\cdot (x^{2}+4\cdot x +3)$

$f(x) = x\cdot (x^{2}+4\cdot x + 3)-6\cdot (x^{2}+4\cdot x +3)$

$f(x) = x^{3}+4\cdot x^{2}+3\cdot x -6\cdot x^{2}-24\cdot x -18$

$f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ (1)

The polynomial in expanded form is $f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18$ .

b) In this question we divide the polynomial found in a) (in factor form) by the polynomial $x^{2}-x -2$ (also in factor form). That is:

$g(x) = \frac{(x-6)\cdot (x+1)\cdot (x+3)}{(x-2)\cdot (x+1)}$

$g(x) = \frac{(x-6)\cdot (x+3)}{x-2}$ (2)

The slant asymptote is defined by linear function, whose slope ( $m$ ) and intercept ( $b$ ) are determined by the following expressions:

$m = \lim_{x \to \pm \infty} \frac{g(x)}{x}$ (3)

$b = \lim_{x \to \pm \infty} [g(x)-x]$ (4)

If $g(x) = \frac{(x-6)\cdot (x+3)}{x-2}$ , then the equation of the slant asymptote is:

$m = \lim_{x \to 2} \frac{(x-6)\cdot (x+3)}{x\cdot (x-2)}$

$m = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x^{2}-2\cdot x} \right)$

$m = 1$

$b = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x-2}-x \right)$

$b = \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x - 18-x^{2}+2\cdot x}{x-2}\right)$

$b = \lim_{n \to \infty} \left(\frac{-x-18}{x-2} \right)$

$b = -1$

The slant asymptote is represented by the linear function is $y = -x + 1$ .

c) The number of discontinuities in rational functions is equal to the number of binomials in the denominator, which was determined in b). Hence, we have a discontinuity at $x = 2$ with a slant asymptote.

We kindly invite to check this question on asymptotes: brainly.com/question/4084552

8 0

2 years ago

PLZ ANSWER <br><br> 1-2x = -X-3

DIA [1.3K]

Answer:

-4=x

Step-by-step explanation:

1) 1-2x=-x-3 (letter's to the left)

2) then you get 1-x=-3

3) then you subtract 1 on both sides

4) then you dived the -1

5)answer -4=x

5 0

3 years ago

Mike practices the cello every 5 days and the piano every 13 days. Mike practiced both the cello and the piano today. How many d

Rus_ich [418]

Answer:

65 days.

Step-by-step explanation:

because 13 multiplied 5 is 65 and 5 multiplied by 13 is also 65.

7 0

3 years ago

Andre is a worker ant who has been busy

Arada [10]

Answer:

2.3 and 23/10

Step-by-step explanation:

2 3/10 as a decimal is 2.3 because u have to move the decimal and u take 10 away from 3/10. 2 3/10 is 23/10 because 2 x 10 = 20 then add 3 to 20 which is 23 then but 23 or 10 and there's ur fraction and when u divide u should get 2.3.

8 0

3 years ago