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AlexFokin [52]
3 years ago
13

In January, you deposit $16 in your checking account. Each month, you deposit $15 more than you did the month before. How much m

oney do you deposit in October?
Mathematics
2 answers:
Leya [2.2K]3 years ago
6 0
You would put 151 dollars in your account at October.
16+15+15+15+15+15+15+15+15+15=151

Ugo [173]3 years ago
3 0

Answer:

<h2>$151</h2>

Step-by-step explanation:

This problem is about a arithmetic sequence, which is obtained by summing a term which is called "difference". In this case, we need to find the tenth term of the arithmetic sequence, because that's the term assigned for October. The formula of an arithmetic sequence is

a_{n}=a_{1}+(n-1)d

Where:

n=10\\a_{1}=16\\d=15

Replacing values, we have

a_{10}=16+(10-1)15=151

Therefore, on October you will have $151 if you deposit $15 more each month, beginning with $16.

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Hunter had $76.00 in his bank account. Hunter made three withdrawals during the
kozerog [31]

Answer:

£26 £23 £27

Step-by-step explanation:

If you add them all up, it will equal £76

3 0
3 years ago
HighTech Inc. randomly tests its employees about company policies. Last year in the 560 random tests conducted, 26 employees fai
Tanzania [10]

Answer:

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

560 random tests conducted, 26 employees failed the test. This means that n = 560, \pi = \frac{26}{560} = 0.046

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.33.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 - 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.025

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 + 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.067

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

5 0
4 years ago
A standard pair of six-sided dice is rolled. What is the probability of rolling a sum less than 7? Express your answer as a frac
zzz [600]

Answer:

0.4167 is the probability of rolling a sum less than 7.  

Step-by-step explanation:

We are given the following in the question:

Event: A standard pair of six-sided dice is rolled

A: rolling a sum less than 7

Sample space:

{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

A:

{(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

Formula:

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(A) = \dfrac{15}{36} = 0.4167

0.4167 is the probability of rolling a sum less than 7.

8 0
3 years ago
Who ever makes polnareff there profile pic is my new friend DONT JUST ANSWER SOMETHING DUM LIKE I DONT KNOW WHO THAT IS OR OK OR
inysia [295]

Step-by-step explanation:

Explain how the author supports the argument that banning plastic bags in favor of paper ones is not a good solution to the problem of waste.

Use details from the article to support your response

7 0
3 years ago
An urn contains 13 red marbles and 14 blue marbles. 16 marbles are chosen at random. what is the probability that 6 red marbles
11111nata11111 [884]
6/43
which means 
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4 0
3 years ago
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