Calculate the speed of a train traveled 400miles in 5 hours
2 answers:
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y - y₁ = m(x - x₁)
y - (-1) = -1¹/₂(x - 3)
y + 1 = -1¹/₂(x) + 1¹/₂(3)
y + 1 = -1¹/₂x + 4¹/₂
- 1 - 1
y = -1¹/₂x + 3¹/₂
4x + y - 2 = 0
+ 2 + 2
4x + y = 2
4x - 4x + y = -4x + 2
y = -4x + 2
y - y₁ = m(x - x₁)
y - (-3) = -4(x - 4)
y + 3 = -4(x) + 4(4)
y + 3 = -4x + 16
- 3 - 3
y = -4x + 13
2x - 3y - 5 = 0
+ 5 + 5
2x - 2x - 3y = -2x + 5
-3y = -2x + 5
-3 -3
y = ²/₃x - 1²/₃
y - (-3) = -1¹/₂(x - 4)
y + 3 = -1¹/₂(x) + 1¹/₂(4)
y + 3 = -1¹/₂x + 6
- 3 - 3
y = -1¹/₂x + 3