1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Talja [164]
3 years ago
14

In the following reaction, how many grams of ammonia (NH3) will produce

Chemistry
2 answers:
IgorLugansk [536]3 years ago
3 0
145.899 grams

Take the 300 grams of N2 you want and divide by its molar mass of 17.0337 to tell you that you want 10.70664 moles of N2. Since for every 5 moles of N2 produced, you need 4 moles of ammonia, divide by 5 and then multiply by 4 to get the number of moles of ammonia you need. This will be 10.70664 / 5 * 4 = 8.56531 moles. Finally multiply by the molar mass of ammonia and you'll know how many grams of ammonia you need. This is 8.56531 * 17.0337 = 145.8989 grams of ammonia which rounds off to 145.899 grams.


lara [203]3 years ago
3 0

Answer:

The correct option is the third option which is 145.899g

Explanation:

From the equation of reaction: 4NH3 + 6NO → 5N2 + 6H2O

First calculate the masses involved in the given equation of reaction.

Mass of ammonia NH3 = 4 x 17.0337= 68.1348

Mass of nitrogen N2 = 5 x 28. 02 = 140.1

Use the following analogy

68.1348g of ammonia produced  140.1g of N2

Yg of ammonia will be produced by 300g of N2 (Using Y as unknown mass)

<em>Calculating for Y by cross-multiplying </em>

Therefore 300g of N2 (Y) will be produced by 68.1348 x 300/ 140.1 = 145.899g

You might be interested in
Select the correct answer. When an atom in a reactant loses electrons, what happens to its oxidation number? A. Its oxidation nu
vfiekz [6]

Answer:

C. Its oxidation number increases.

Explanation:

  • <em><u>Oxidation is defined as the loss of electrons by an atom while reduction is the gain of electrons by an atom</u></em>.
  • Atoms of elements have an oxidation number of Zero in their elemental state.
  • When an atom looses electrons it undergoes oxidation and its oxidation number increases.
  • For example, <em><u>an atom of sodium (Na) at its elemental state has an oxidation number of 0. When the sodium atom looses an electrons it becomes a cation, Na+, with an oxidation number of +1 , the loss of electron shows an increase in oxidation number from 0 to +1.</u></em>
8 0
3 years ago
Read 2 more answers
14. All the following are necessary parts of a neutralization reaction except A. an indicator. B. a salt. C. water. D. an acid.
ValentinkaMS [17]

The correct answer is <em>B. a Salt </em><em>because The reaction of an acid and a base is called a neutralization reaction because the properties of both the acid and base are diminished or neutralized when they react. A neutralization reaction is a reaction of an acid with a base in aqueous solution to produce water and a salt, as shown by the following equation:</em>

<em>acid + base → salt + water</em>

<em />

<em>* Hopefully this helps:) Mark me the brainliest:) </em>

<em>∞ 234483279c20∞</em>

6 0
3 years ago
What is the atomic number of hydrogen
olga nikolaevna [1]
The atomic number of hydrogen is 1
8 0
3 years ago
How much energy is released when 0.40 mol C6H6(g) completely reacts with oxygen?
Vsevolod [243]
 <span>This question asksyou to apply Hess's law. 
You have to look for how to add up all the reaction so that you get the net equation as the combustion for benzene. The net reaction should look something like C6H6(l)+ O2 (g)-->CO2(g) +H2O(l). So, you need to add up the reaction in a way so that you can cancel H2 and C. 
multiply 2 H2(g) + O2 (g) --> 2H2O(l) delta H= -572 kJ by 3 
multiply C(s) + O2(g) --> CO2(g) delta H= -394 kJ by 12 
multiply 6C(s) + 3 H2(g) --> C6H6(l) delta H= +49 kJ by 2 after reversing the equation. 
Then, 
6 H2(g) + 3O2 (g) --> 6H2O(l) delta H= -1716 kJ 
12C(s) + 12O2(g) --> 12CO2(g) delta H= -4728 kJ 
2C6H6(l) --> 12 C(s) + 6 H2(g) delta H= - 98 kJ 
______________________________________... 
2C6H6(l) + 16O2 (g)-->12CO2(g) + 6H2O(l) delta H= - 6542 kJ 
I hope this helps and my answer is right.</span>
4 0
3 years ago
Read 2 more answers
Various plant and animal species are on the verge of extinction.
olga2289 [7]

Answer:

  1: A.) adapted

  2: A.) habitat destruction

Explanation:

Some (few) animals are capable of adjusting their behaviors in relation to human activity and the changes humans make in their habitat. Most are so well adapted to the details of their habitat that they are incapable of surviving when those details change.

"Because all organisms are <u>adapted</u> to their native habitat, human activities that result in <u>habitat destruction</u> are a major reason for their extinction."

_____

<em>Comment on human activities</em>

My friendly local rodent exterminator observed that rodent activity has picked up substantially, since so much human activity has been curtailed by quarantine orders.

3 0
4 years ago
Other questions:
  • What is the molarity of a 10.2 % by mass glucose (c6h12o6) solution? (the density of the solution is 1.03 g/ml .)?
    7·1 answer
  • The melting point of a compound is 1240 c is this compound an ionic or molecular compound
    14·1 answer
  • Which best describes emerging scientific ideas?
    5·1 answer
  • Where are the most active nonmetals located?​
    9·1 answer
  • Dependent variable? ( what did we measore)?
    12·1 answer
  • The type of nuclear decay an unstable nucleus will undergo depends on its ratio of neutrons to protons. The radioisotope cobalt-
    12·2 answers
  • Substances that cannot be broken down into simpler substances are called ____________.
    15·2 answers
  • The exact position of the electrons of an atom cannot be determined because they are in constant ___
    12·1 answer
  • Which characteristic is a property of water
    10·1 answer
  • A piece of chalk, has an initial mass of 43. 5 grams. The mass of the chalk decreased to 39. 6 grams after use. Which of these i
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!