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Umnica [9.8K]
3 years ago
12

Dependent variable? ( what did we measore)?

Chemistry
1 answer:
lana66690 [7]3 years ago
6 0
The thing u change.
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Why is frying an egg an example of a chemical change
skelet666 [1.2K]
A Chemical change is any form of chemical reaction changing the state of the matter involved. When you fry an egg, you are making a reaction between the heat and the chemicals that make up the egg. Therefore once you have fried that egg, you have completed a chemical reaction. This is why it's a chemical change when you fry an egg.
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Fluorine + sodium chloride → sodium fluoride + __________. What is the missing chemical name?
Deffense [45]

Answer:

Chlorine (Cl)

Explanation:

The equation would be:

F+NaCl  → NaF + Cl

This is because no atom is lost in a reaction. Chlorine would be the missing chemical as it is on the other side of the equation and needs to be accounted for on the products side.

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3 years ago
Select odd one out.<br> I) O<br> II) Na<br> III) Cu<br> IV) Ag
USPshnik [31]

Explanation:

0 is the odd one...............

and rest are metals and they lose electron and 0 gain electron and is non metal

4 0
3 years ago
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Identify the f-block element.
GaryK [48]

Answer: E. none of these

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3 0
3 years ago
After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid
nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\

Then, we add the half reactions:

2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0
3 years ago
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