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Paha777 [63]
3 years ago
7

I’m still confused on how to work the percentages

Mathematics
2 answers:
juin [17]3 years ago
6 0

Answer: 13 students


Step-by-step explanation: If you look there's 30 students, and most students like cats because the color is the biggest. Therefore, the answer is 13 students.


Serjik [45]3 years ago
5 0

Answer:

13 is your answer

Step-by-step explanation:

it's the biggest number and more students like cats

Hope this helps

God bless you

Have a great day

- Kayla :)

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If f(x) is a continuous function defined for all real numbers, f(–1) = 1, f(–5) = –10, and f(x) = 0 for one and only one value o
Mashcka [7]
The answer is would be B. -5
4 0
3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
PLEASE HELP EASY POINTS
miv72 [106K]
What is the question?
6 0
3 years ago
Read 2 more answers
Solve the given equation. ( 1/5 )( 4/7 )x = 32/490 (x is and exponent) x= _____
Vikki [24]
X= 4/7 because it would be

4/35x=16/245

which would be 28x=16

simplified it would be 4/7
5 0
3 years ago
A very large book is numbered to 1 to 11521 How many digits are used to print all these page numbers
stealth61 [152]

Answer:

46,499 digits

Step-by-step explanation:

Total pages of book = 11,521

9 pages numbered 1 - 9 that need 1 digit each = 9 × 1

= 9 digits

90 pages numbered 10 - 99 that need 2 digits each = 90 × 2

= 180 digits

900 pages numbered 100 - 999 that need 3 digits each = 900 × 3

= 2,700 digits

9000 pages numbered 1000 - 9999 that need 4 digits each = 9000 × 4

= 36,000 digits

1522 pages numbered 1000 - 11521 that need 5 digits each = 1522 × 5

= 7,610 digits

Total digits needed = 9 digits + 180 digits + 2,700 digits + 36,000 digits + 7,610 digits

= 46,499 digits

5 0
3 years ago
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