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Vera_Pavlovna [14]
3 years ago
13

Between 2016 and 2018 how many kg of boulders were excavated?​

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0
I’ll read this later and try to help you!
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“The length of the unknown side has to be greater than ___ and less than ___.” PLEASE HELP, WILL GIVE BRAINLIEST
BartSMP [9]

Answer:

7< 8

Step-by-step explanation:

8 0
3 years ago
sweet t has 2 orange picks for every five green. if there are 21 picks in all, how many picks are orange
jarptica [38.1K]
21 picks
altogether (2x+5x)=21
7x=21
x=3
2*3=6 orange picks

or
x=orange, y = greens
x+y=21
x/y=2/5,---->   y=5x/2
x+5x/2=21
2x/2+5x/2=21
7x/2=21
7x=42,
x=6  orange picks





3 0
3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
Analyze the diagram below and complete the instructions that follow?
yan [13]

Answer:

The exact value of tan(M) is 5/12 ⇒ answer (C)

Step-by-step explanation:

* Lets revise the trigonometry functions

- In ΔABC

# m∠B = 90°

# Length of AB = a , length of BC = b and length of AC = c

# The trigonometry functions of angle C are

- sin(C) = a/c ⇒ opposite side to ∠C ÷ the hypotenuse

- cos(C) = b/c ⇒ adjacent side to ∠C ÷ the hypotenuse

- tan(c) = a/b ⇒ opposite side to ∠C ÷ adjacent side to ∠C

* Now lets solve the problem

- In ΔONM

∵ m∠N = 90°

∵ MN = 12

∵ ON = 5

∵ tan(M) = ON/NM ⇒ opposite side of ∠(M) ÷ adjacent side of ∠(M)

∴ tan(M) = 5/12

* The exact value of tan(M) is 5/12

6 0
4 years ago
Write the equations for the graphs below (worth 5 points) ​
serg [7]
Answers:

10) y= 1/2x - 2
11) y= 2x + 3
12) y= 2/3x - 4

I found this by using y=mx+ b
3 0
3 years ago
Read 2 more answers
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