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3 years ago

I have two questions to solve -3x+10=34 13x-4=11x+10-8

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

7 0

You answered it ....................34 and2

Marina CMI [18]3 years ago

5 0

-3x + 10 = 34

Subtract 10 from both sides:

-3x = 24

Divide both sides by -3:

X = 24 / -3

X = -8

musiclover10045

Middle School Mathematics 39+20 pts

I have two questions to solve

-3x+10=34

13x-4=11x+10-8

Combine like terms on the right side:

13x -4 = 11x + 2

Subtract 11x from both sides:

2x -4 = 2

Add 4 to both sides:

2x = 6

Divide both sides by 2:

X = 6/2

X = 3

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3 years ago

Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

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Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

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Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

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Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

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3 years ago

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Answer:

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A. Y=-1/2x+2<br> B. Y=1/2x+2<br> C. Y=-2x-3<br> D. Y=2x-6

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Answer:

B: Y=1/2×+2 I think that's it

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