First, find the x-intercept.
The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.
5y + 3x = 15
5(0) + 3x = 15
3x + 15
x = 5
We found the x-intercept now find the y-intercept with the same process.
The y-intercept will be at the point (0, y) where y is any real number.
5y + 3x = 15
5y + 3(0) = 15
5y = 15
y = 3
So, the x-intercept is (5, 0) and the y-intercept is (0, 3)
- Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.
(Make sure to set f(x) to zero)
So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: 
Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: 
Now you can rewrite the equation as: 
Now apply zero product property to the factors to solve for x:
<u>The x-intercepts are (1/5 ,0) and (-1,0).</u>
Answer:
73
Step-by-step explanation:
to find the mean you need to add up all grades and divide if by the number of terms you added
(82 + 88 + x) ÷ 3 = 69 (since we don't know the third grade let's call it x)
170 + x = 69 × 3
x = 37
if the digits transposed the the actual grade would be 73
6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1
6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5
.375 because 1/50= .02 and 1/10=.01 which are both less than .375
