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Oxana [17]
3 years ago
12

I have two questions to solve -3x+10=34 13x-4=11x+10-8

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0
You answered it ....................34 and2
Marina CMI [18]3 years ago
5 0

-3x + 10 = 34

Subtract 10 from both sides:

-3x = 24

Divide both sides by -3:

X = 24 / -3

X = -8

musiclover10045

Middle School Mathematics 39+20 pts

I have two questions to solve

-3x+10=34

13x-4=11x+10-8

Combine like terms on the right side:

13x -4 = 11x + 2

Subtract 11x from both sides:

2x -4 = 2

Add 4 to both sides:

2x = 6

Divide both sides by 2:

X = 6/2

X = 3

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(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

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(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

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4x-6y=3\\-\\4x-6y=6\\------\\0=-3

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(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

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Substitute x=\frac{5+3y}{2} into the second equation

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The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

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Answer:

B: Y=1/2×+2 I think that's it

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2 years ago
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