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Oxana [17]
3 years ago
12

I have two questions to solve -3x+10=34 13x-4=11x+10-8

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0
You answered it ....................34 and2
Marina CMI [18]3 years ago
5 0

-3x + 10 = 34

Subtract 10 from both sides:

-3x = 24

Divide both sides by -3:

X = 24 / -3

X = -8

musiclover10045

Middle School Mathematics 39+20 pts

I have two questions to solve

-3x+10=34

13x-4=11x+10-8

Combine like terms on the right side:

13x -4 = 11x + 2

Subtract 11x from both sides:

2x -4 = 2

Add 4 to both sides:

2x = 6

Divide both sides by 2:

X = 6/2

X = 3

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sergejj [24]

Answer:

102°

Step-by-step explanation:

As the vertically opposite angles are equal,

5x+2={3(x+14)

Now let's solve for x now

5x+2=3(x+14)\\

5x+2=3x+42

5x-3x=42-2

2x=40

\frac{2x}{2} =\frac{40}{2}

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Hope this helps you.

Let me know if you have any other questions ;-)

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2 years ago
A quadratic function is defined by
ella [17]

Answer:

1. The vertex of the graph of the function is (-4, 7)

2. The vertex represents a minimum value

3. The equation represented by the new graph is g(x) = (x + 4)² + 1

Step-by-step explanation:

The given quadratic function is given in vertex  form, y = a·(x - h)² + k, as follows;

g(x) = (x + 4)² + 7

1. By comparing the given quadratic function and the vertex form of a quadratic equation, we have;

a = 1, h = -4, and k = 7

The vertex of the graph of the function, (h, k) = (-4, 7)

2. Given that a = 1 > 0, the graph of the quadratic function opens upwards and the vertex represents a minimum value

3. Shifting the graph 6 units down from where it is now will give;

The vertex = (h, k - 6) = (-4, 7 - 6) = (-4, 1)

h = -b/(2·a), k = (-b²/(4·a) + c = -a·h² + c

c = k + a·h²

Therefore, initial value of the constant term, c = -1×(-4)² + 7 = 23

After the shifting the graph 6 units down, c = 23 - 6 = 17

∴ k = 1 = -a·(-4)² + 17

∴ -16/16 = -1 = -a

a = 1

Therefore, the equation represented by the new graph is g(x) = (x + 4)² + 1.

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3 years ago
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Maru [420]
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3 years ago
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