1/2=4/8
4/8 less than 5/8
Good Luck!
Whats the problem? just substitute. For example: 3x-5 if x=4 so what you do is this; 3(4)-5=7
Using it's concept, it is found that there is a 0.125 = 12.5% experimental probability that a randomly selected preschooler would choose to read books today.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
For an experimental probability, these numbers of outcomes are taken from previous trials.
In this problem, in the previous trial, one out of eight students read a book, hence:
p = 1/8 = 0.125 = 12.5%.
There is a 0.125 = 12.5% experimental probability that a randomly selected preschooler would choose to read books today.
More can be learned about probabilities at brainly.com/question/14398287
Answer:
12 / (-15) goes in the first box.
12 / 15 goes into the second box
15 / -12 goes into the third box
and 15 / 12 goes into the fourth box
Step-by-step explanation:
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213