I chose the wrong screenshots for the last one, sorry about that!

A car can drive 476 miles on 14 gallon

Degger [83]

What is the question?

8 0

2 years ago

2. What is the length of the horizontal line segment joining points C(-9,205) and D(4,205)?

arsen [322]

Answer:

13 unit

Step-by-step explanation:

................

3 0

2 years ago

Bird and reptiles both lay hard shelled eggs Birds and fish have jaws birds

Mashcka [7]

Answer:

yes?

Step-by-step explanation:

the question is unclear

4 0

2 years ago

Read 2 more answers

Vector V is in standard position and makes an angle of 50° with the positive x-axis. Its magnitude is 15. Write V in component f

Scilla [17]

Answer:

a=9.641, b=11.49

Vector will be 9.641 i + 11.49 j

Step-by-step explanation:

We have given that vector V has the magnitude of 15

And it makes an angle of 50 $^{\circ}$ with positive x axis

Now let the x component of vector V is a and y component of vector V is b

So $a=Vcos\Theta =15\times cos50^{\circ}=9.641$

$b=Vsin\Theta =15\times sin50^{\circ}=11.49$

In vector form 9.641 i+11.49 j

8 0

3 years ago

An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Fynjy0 [20]

Answer:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

$\bar X=31.1$ represent the sample mean

$\sigma=1.3$ represent the population standard deviation

$n=140$ sample size

$\mu_o =31.3$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:

Null hypothesis: $\mu =31.3$

Alternative hypothesis: $\mu \neq 31.3$

Since we know the population deviation, the statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

4 0

3 years ago