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ohaa [14]
3 years ago
15

What are the points of discontinuity? Are they removable? y = (x-5) / x^2 - 6x + 5

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

The points of discontinuity are: x=5 and x=1. The point of discontinuity x=5 can be removable.

Step-by-step explanation:

The points of discontinuity are those points where the function is not defined. To find such points, we should factorize the denominator of the function needs to be factorized.

                                        y= (x-5)/(x^2 - 6x + 5)

Considering the quadratic equation of the form ax^2+bx+c =0, then using the quadratic (see attached image), where a=, b=- and c=5, we have that the roots are:

                                              x=5 and x=1.

If we simplify the fraction, by removing the term (x-5) from both the numerator and the denominator, we get: y=1/(x-1), so we removed the point of discontinuity x=5.

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when you reverse the digits in a certain two-diget number you increase it value by 27. What is the number if the sum of its digi
Fynjy0 [20]
The number is = 10x+y
if reverse the digits, the number is: 10y+x
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I suggest this system of equations:
(10y+x)-(10x+y)=27    ⇒9y-9x=27
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We can solve this system of equations by equaliztion method
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Step-by-step explanation:

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What is the slope of the line joining (8,8) and (12, 6)?
Anna71 [15]

Answer:

\huge \boxed{ \boxed{ -  \frac{1}{2} }}

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\

From the question we have

m =  \frac{6 - 8}{12 - 8}  =  -  \frac{2}{4}  =  -  \frac{1}{2}  \\

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Need math help (last one wouldn't let me upload pic)
Scrat [10]

Answer:

\text{Area of the figure}=54\text{ unit}^2

Step-by-step explanation:

Please find the attachment.

Let us divide our given image in several parts and then we will find area of different parts.

First of all let us find the area of our red rectangle with side lengths 6 units and 7 units.

\text{Area of rectangle}=\text{Length*Width}

\text{Area of red rectangle part}=6\text{ units}\times 7\text{ units}

\text{Area of red rectangle part}=42\text{ units}^2

Now let us find area of yellow triangle on the top of red rectangle. We can see that base of triangle is 6 units and height is 1 unit.

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Let us find the area of green triangle.

\text{Area of green triangle}=\frac{1}{2}\times \text{3 units *2 units}

\text{Area of green triangle}=3\text{ unit}^2

Now we will find the area of blue triangle, whose base is 6 units and height is 2 units.

\text{Area of blue triangle}=\frac{1}{2}\times \text{6 units *2 units}

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Let us add all these areas to find the area of our figure.

\text{Area of the figure}=42\text{ units}^2+3\text{ unit}^2+3\text{ unit}^2+6\text{ unit}^2

\text{Area of the figure}=(42+3+3+6)\text{ unit}^2

\text{Area of the figure}=54\text{ unit}^2

Therefore, area of our given figure is 54 square units.  

3 0
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