2p=p(1+0.0075/12)^12t
12t=log(2)/log(1+0.0075/12)
Can you solve for t
Simplify the following:
(y^6 y^8)/((2 x^2)/(x^4))
Combine powers. (y^6 y^8)/((x^2×2)/x^4) = (y^(8 + 6) x^(4 - 2))/2:
(y^(8 + 6) x^(4 - 2))/2
8 + 6 = 14:
(y^14 x^(4 - 2))/2
4 - 2 = 2:
Answer: (y^14 x^2)/2
B. 17.16 represents a credit of $17.16; "credits" mean that you're receiving something, so it's added. A is incorrect because it shows the money being taken away and that isn't what a credit does. C and D aren't even the same amount of money in the question, so they aren't your answer either.
Answer:
Neither.
Step-by-step explanation:
I am not completely sure, so make sure to also let other answer this before you trust me lol. I really hope this helps!!
Answer:666 hours
Step-by-step explanation: The reason is that if you turn the problem into an equation it would be h=Lx. h= hours. L=how long the log lasts and x=how many logs. So when you plug in the numbers you get 101010=L*151515. So we need to find L. What you do is you divide both sides by 151515 since it is the opposite of multiplication. 151515/151515 gets crossed out and 101010/151515 is .6666666666666 irrational. So the equation now looks like .666666 irrational=L. So .66666 irrational is your L. Know you plug .666666 irrational into your original equation. Which is now h=.6666 irrational*x. So to find how long the fire keeps on burning with 999 logs you just plug 999 into x and now your equation looks like this h=.6666 irrational*999. If you multiply .6666 irrational by 999 your final answer is 666.
