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Stella [2.4K]
3 years ago
5

Slope-intercept form for the line with y-intercept 5 and slope-1/4​

Mathematics
1 answer:
valkas [14]3 years ago
4 0

Answer:

y = -1/4x + 5

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

y = -1/4x + 5

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Jace invested $65,000 in an account paying an interest rate of 2.5% compounded continuously. Assuming no deposits or withdrawals
Tomtit [17]

Answer:

15 years

Step-by-step explanation:

93400=65000*e^(.025x)

x=14.5 which rounds to 15

7 0
3 years ago
Is 7/3 a rational number ?
boyakko [2]

Answer: Yes

Step-by-step explanation: To determine whether 7/3 is a rational number, remember all fractions either positive or negative are rational numbers.

Therefore, 7/3 is a rational number.

4 0
3 years ago
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If Pablo invest $4,200 for 3 years and earn $630 what is the simple interest rate
Mariana [72]
The interest rate would be 5%
6 0
4 years ago
An error has been made in subtracting the two polynomials shown in the work below the problem is (6x^2-4x-5)-(3x^2-7x=2)
MissTica

Answer/Step-by-step explanation:

Let's work out the subtraction of the polynomial to find out where the error is and the correct result we should have.

6x² - 4x - 5

- 3x² - 7x + 2

= [6x² - 3x²] [-4x -(-7x)] [-5 -(+2)]

= 3x² + 3x - 7

The error that was made in the subtraction given in the question was that the negative signs before the terms, 7x and 5 were ignored while subtracting.

The sign is very important, it defines the value of the term.

We can choose to solve the problem in another way shown below:

(6x² - 4x - 5) - (3x² - 7x + 2)

Distributive the negative sign in the second polynomial

6x² - 4x - 5 - 3x² + 7x - 2

Combine like terms

6x² - 3x² - 4x + 7x - 5 - 2

3x² + 3x - 7

7 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
3 years ago
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