9514 1404 393
Answer:
-13/11
Step-by-step explanation:
Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...
![\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto%201%7D%5Cdfrac%7Bn%7D%7Bd%7D%3D%5Cdfrac%7Bn%27%7D%7Bd%27%7D%3D%5Cleft.%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%5Csqrt%5B3%5D%7B4x-3%7D%7D-%5Cdfrac%7B7%7D%7B2%5Csqrt%7B7x-6%7D%7D%7D%7B%5Cdfrac%7B5%7D%7B2%5Csqrt%7B5x-4%7D%7D-%5Cdfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B2x-1%7D%7D%7D%5Cright%7C_%7Bx%3D1%7D%3D%5Cdfrac%7B4%2F3-7%2F2%7D%7B5%2F2-2%2F3%7D%3D%5Cdfrac%7B8-21%7D%7B15-4%7D%5C%5C%5C%5C%3D%5Cboxed%7B-%5Cdfrac%7B13%7D%7B11%7D%7D)
So 4's facts
we know that 4 times 2=8 and the associative property of multiplication says
a(bc)=(ab)c
so 7(8) (means 7 times 8) means 7((4)(2)) and associative say we can group them and say (7)(4)(2) so (4)((7)(2)) or 4(14) and 4 times 14=56
7 times 8=56
Answer: The median, because the data distribution is skewed to the left
EXPLANATION
Given the box plot with the following parameters:
Minimum value at 11
First Quartile, Q1 at 22.5
Median at 34.5
Third Quartile, Q3 at 36
Maximum value at 37.5
First, we notice that the data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile
(22.5).
Furthermore, we know that the mean provides a better description of the center when the data distribution is symmetrical while the median provides a better description of the center when the data distribution is skewed.
Therefore, we conclude that for the given box plot, the median will provide a better description of the center because the data distribution is skewed to the left.
Answer:
the fist one is equal to 20
I think #4 is 4 but I'm not completely sure
