Please help geometry problems
1 answer:
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Answer:
. hole or removable discontinuity at x=2
Step-by-step explanation:
Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)
So let's start by factoring the first equation:
Now let's find what ac is (it's just c since a=1...)
List factors of -6
.
Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...
So using these two factors we get
Ok now let's factor the second equation:
Multiply a and c
List factors of 12:
.
Factors that add up to -7 and multiply to 12:
Rewrite equation:
Group terms:
Factor out GCF:
Rewrite:
Now let's write out the equation using these factors:
.
Here we can factor out the x-2 and the simplified form is:
So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.
Answer:
The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.
The probability that a randomly chosen plate contains the sub-string HI is 0.002548 approximately.
Step-by-step explanation:
Consider the provided information.
Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
Part (A)
Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.
Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.
The numbers of ways in which three letters followed by three digits can be chosen is:
The numbers of ways in which two letters followed by four digits can be chosen is:
Hence, the total number of ways are 17576000 + 6760000 = 24336000
Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.
Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are:
The probability that a randomly chosen plate contains the number 2222 is:
Part (B)
The number of ways in which chosen plate contains the sub-string HI:
If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:
If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:
Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:
From part (A) we know that the total number of ways to chose a number plate is 24336000.
The probability that a randomly chosen plate contains the sub-string HI is: