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3 years ago

Please help geometry problems

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

1. x=4
2. x=7
3. x=4
I hope this helped!

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Please answer Number 5

DedPeter [7]

Answer:

what is the question, you forgot to add the image.

Step-by-step explanation:

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3 years ago

Which property of addition is used in the following (5+12)+6=5+(12+6)

Marianna [84]

Answer:

Associative property of addition

Step-by-step explanation:

its the same order only the () move

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3 years ago

I need help 1.09 divided by 3.08 show your solution Thank you so much if u helpt me

gayaneshka [121]

Answer:

<h2 /><h2>answer will be 0.3538</h2>

Step-by-step explanation:

$\frac{1.09}{3.08} = 0.3538$

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3 years ago

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

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3 years ago

How do you simplify (4/9)²?

Vanyuwa [196]

(4/9)² = 4²/9² = 16/81

7 0

3 years ago