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3 years ago

Help me please I am not good at this stuff

Mathematics

2 answers:

DaniilM [7]3 years ago

4 0

Answer:

45 square inches

Step-by-step explanation:

Mrrafil [7]3 years ago

3 0

<h2>○=> Correct answer :</h2><h2> $\color{plum} = \tt\bold{30 \: cubic \: inches}$ </h2><h3>○=> Steps to derive correct answer :</h3>

Given :

Area of base of a triangular pyramid = 9 inches

Length of height of triangular pyramid = 10 inches

We know that :

$\tt \: \color{hotpink}volume\: of \: a \: triangular \: pyramid \color{plum}= \frac{1}{3} Bh$

Which means :

Volume of this triangular pyramid :

$= \tt \frac{1}{3} \times 9 \times 10$

$=\tt \frac{9 \times 10}{3}$

$=\tt \frac{90}{3}$

$\color{plum} =\tt 30 \: {inches}^{3}$

Thus, the volume of this pyramid = 30 inches³

You might be interested in

The 8 foot diameter circular table has a 4 foot wide extension. What is the total area with the extension? How does the area com

galina1969 [7]

Answer: the total area with the extension S≈82,3 foot², S>S'.

Step-by-step explanation:

D₁=8 foot D₂=10 foot a wide extension = 4 foot.

1) Let the total area with the extension S is the area of the circular table S₁

plus a wide extension S₂.

Considere S₁:

$R_1=\frac{D_1}{2} \\R_1=\frac{8}{2} \\R_1=4 foot.\\S_1=\pi* R_1^2\\S_1=\pi *4^2\\S_1=16*\pi \\S_1\approx50,3\ foot^2.\\$

$S_2=8*4\\S_2=32 \ foot^2.$

$S\approx50,3+32\\S\approx82,3 \ foot^2.$

2)\ Considere S':

$R_2=\frac{D_2}{2} \\R_2=\frac{10}{2} \\R_2=5 \ foot.\\S'=\pi *R^2\\S'=\pi *5^2\\S'=25*\pi \\S'\approx78,5\ foot^2.$

S>S'.

Good luck an' have a nice day!

3 0

2 years ago

What is x in ax+3x=bx-5

Keith_Richards [23]

Answer:

The answer is provided in the image below.

X= negative fraction 5/a+3-b

5 0

3 years ago

Fabiano and Sonali's teacher gave them a system of linear equations to solve. They each took a few steps that led to the systems

marin [14]

Question: Which system has the same solution as the teacher's system?

Systems of equations that have the same solution are called equivalent systems.We are given with a system of two equations, we can make an equivalent system by substituting one equation by the sum of the two equations.

Given System:
<span>
8x-16y=14</span>→eq.1
−x+5y=−3→eq.2<span>
Teacher's Solution:
From eq.2
x = 5y + 3
Substituting the value of x in eq.1
We get,
</span> 8(5y + 3) - 16y = 14
40y + 24 - 16y = 14
24y + 24 = 14
24y = 14-24
24y = -10
y = -10/24
y = -5/12

Substituting y-value in eq.2,
−x+5(-5/12) = −3
-x -25/12 = -3
-x = -3 + 21/12
-x = 15/12
x = -5/4

<span>Fabiano:
</span> 3x−15y=<span>9
</span> 8x−16y=−<span>7

</span>Rearranging both equations:
y = 1/5x - 3/5
y = 1/2x+7/16

Placing both equations equal to each other,
1/5x - 3/5= 1/2x+7/16
1/5x -1/2x = 7/16 +3/5
-3/5x = 83/80
x = -83×5/80×3
x = -415/240
x = -83/48
This doesnt matches the teachers solution so we will move to sonali.

<span>Sonali
</span> −x+5y=−<span>3
</span> −4x+8y=−7
Rearranging both equations:
y = 1/5x - 3/5
y = 1/2x -7/8

Placing both equations equal to each other,
1/5x - 3/5 = 1/2x -7/8
1/5x -1/2x = -7/8 +3/5
-3/10x = -11/40
x = 110/120
x = 11/12

This doesn't match the teacher's solution either, so we will conclude that none of the solutions to the system of equation has the same answer as the teacher.