C. The graph g(x) = x − 7 is the result of translating the graph of f(x) = x + 3 down 10 units.
Sure hope this helps you and good on whatever math test or exam is coming up soon!! :D
Answer:
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Step-by-step explanation:
Answer:
the amswer is c
Step-by-step explanation:
Answer:
Step-by-step explanation:
Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.
Examples
(a) 
From above, we have a power to a power, so, we can think of multiplying the exponents.
i.e.


Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.
SO;


Let's take a look at another example

Here, we apply the
to both 27 and 


Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.
∴
![= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)](https://tex.z-dn.net/?f=%3D%20%5CBigg%20%28%5Csqrt%5B3%5D%7B27%7D%5E%7B5%7D%20%5Ctimes%20x%5E%7B10%7D%20%7D%5CBigg%29)


Answer:
Midpoint (x , y) of two points is
( x1 + y1/2 , x2 + y2/2)
Midpoint of KL is M ( -8 , 1)
Let the coordinates of L be ( a , b)
From the above definition
Midpoint between K(-6 , 5) and
L ( a ,b) is
(-8 , 1) = ( -6+a/2 , 5+b/2)
Comparing first point with - 8
- 8 = -6 + a /2
Multiply through by 2
We get
-16 = - 6 + a
a = -16+6
a = - 10
Comparing the second point with 1
1 = 5+b/2
Multiply through by 2
2 = 5 + b
b = 2 - 5
b = -3
Therefore a = -10 and b = - 3
Hence the coordinates of
L is ( -10 , - 3)
Hope this helps