Yes, it can. Side 22cm can be the hypotenuse (longest side in a right angled triangle) while the others can be shorter sides. These sides form a RIGHT-ANGLED TRIANGLE.
The Area of the Rectangle = l × w
<> 10 × 8 = 80 ft²
The Area of the Semicircle = ½
The Area of a circle = ½ (πr²)
<> π = 3.14
<> r = ½ of 8 = 4 ft
<> ½(3.14 × 4) = 6.28 ft²
The Area of the figure = Area of rectangle + Area of semicircle:-
<> 80 ft² + 6.28 ft² = <u>86.28</u><u> </u><u>ft</u><u>²</u>
Therefore, The area of the figure is <u>86.28</u><u> </u><u>ft</u><u>²</u>.
we can say that there are 15 male teachers for every 35 female teacher
![\stackrel{\textit{\large ratio 1}}{\cfrac{15}{35}\qquad \cfrac{male}{female}} ~\hspace{10em} \stackrel{\textit{\large ratio 2}}{\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{7}{~~\begin{matrix} 35 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{3}{7}\qquad \cfrac{male}{female}}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5Clarge%20ratio%201%7D%7D%7B%5Ccfrac%7B15%7D%7B35%7D%5Cqquad%20%5Ccfrac%7Bmale%7D%7Bfemale%7D%7D%20~%5Chspace%7B10em%7D%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20ratio%202%7D%7D%7B%5Ccfrac%7B%5Cstackrel%7B3%7D%7B~~%5Cbegin%7Bmatrix%7D%2015%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%7B%5Cunderset%7B7%7D%7B~~%5Cbegin%7Bmatrix%7D%2035%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B7%7D%5Cqquad%20%5Ccfrac%7Bmale%7D%7Bfemale%7D%7D)
