I would say C hope I’m not to late :’)
Given:
One of the legs of a right triangle is 9 cm.
The area of the triangle is 225 cm².
To find:
The length of the other leg.
Solution:
The area of a triangle is

The area of a right triangle is

Let x be the length of other leg.




Therefore, the length of the other leg is 50 cm.
Correct answer is: distance from D to AB is 6cm
Solution:-
Let us assume E is the altitude drawn from D to AB.
Given that m∠ACB=120° and ABC is isosceles which means
m∠ABC=m∠BAC = 
And AC= BC
Let AC=BC=x
Then from ΔACD , cos(∠ACD) = 
Since DCB is a straight line m∠ACD+m∠ACB =180
m∠ACD = 180-m∠ACB = 60
Hence 

Now let us consider ΔBDE, sin(∠DBE) = 
