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allochka39001 [22]
2 years ago
7

Leon got a reduction of $40 on a Geometry set

Mathematics
2 answers:
Sindrei [870]2 years ago
7 0
A) 40/480 reduced to 1/12

B) (1/12) x 100 = 8.33%

C) 100% - 8.33% = 91.67%
SSSSS [86.1K]2 years ago
6 0
I pretty sure this one is b
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alexdok [17]
There’s the link to this answer
8 0
3 years ago
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maksim [4K]
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3 years ago
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nirvana33 [79]
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7 0
3 years ago
One of the legs of a right triangle is 9 cm. If the area of the triangle is 225 cm², then the length of the other leg is
ioda

Given:

One of the legs of a right triangle is 9 cm.

The area of the triangle is 225 cm².

To find:

The length of the other leg.

Solution:

The area of a triangle is

Area=\dfrac{1}{2}\times Base\times Height

The area of a right triangle is

Area=\dfrac{1}{2}\times (leg_1)\times (leg_2)

Let x be the length of other leg.

225=\dfrac{1}{2}\times (9)\times (x)

2\times 225=9x

\dfrac{450}{9}=x

50=x

Therefore, the length of the other leg is 50 cm.

4 0
2 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
3 years ago
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