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sladkih [1.3K]
3 years ago
10

With respect to a personal loan, the finance charge a borrower pays is _____. A. The extra money he or she pays in interest B. S

omething the borrower can opt out of with good credit C. An income tax on the loan D. Usually a one time $20 application processing fee
Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0
<h3>Answer: A) extra money paid in interest</h3>

When you get financing, it's another way of saying you get a loan. When you pay back the loan, you pay back the original amount borrowed (principal) plus interest. The term "interest" is interchangeable with "finance charge". In a sense, they are charging you money to let you borrow or finance. With good credit, the interest rate is likely to be lower, and therefore the finance charge would be lower as well. There is a very high chance that all loans use interest or else the bank wouldn't make any money.

jolli1 [7]3 years ago
6 0

Answer:

The answer is A.

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We can put it together: 
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The number you are looking for is 84.
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In creating a new scale for the mercury thermometer, anders celsius initially set the boiling point of water at _____. a. 0° b.
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Step-by-step explanation:

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A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
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Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

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3 years ago
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