You would use 6 = (0.08)w
X <= -2 and 2x >= 6 is the smae as
x<= -2 Nd x >+ 3
Now x cannot satisfy both inequalities so the first one has no solution
First set up an equation in n:-
3n + 10 = 8n
add -3n to both sides;-
10 = 5n
Answer:
refer to explanation
Step-by-step explanation:
the lengths of the base and height are the factors of 20
so they can be 5×4, 10×2, 1×20
1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below:
</span>
B=k/H
B is the base of the triangle (B=10).
H is the height of the triangle (H=6).
k is the constant of variation.
2. When you clear "k", you obtain:
B=k/H
k=BxH
k=10x6
k=60
3. Now, you have:
B=60/H
4. You can give any value to "H" and you will obtain the base of the second triangle.
5. If H=12, then:
B=60/H
B=60/12
B=5
6. Therefore, <span>the possible base and height of a second triangle is:
</span>
B=5
H=12
