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just olya [345]
3 years ago
9

Complete the missing value in y - 4 = -2(x + 3)

Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

y=-2x-2

Step-by-step explanation:

y-4=-2(x+3)

y=-2x-6+4

y=-2x-2

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(5,9), (5-3)<br> what is the slope?
monitta

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

When you want to find out what the slope is, you have to remember what the formula is first....

m=\frac{y}{x} =\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

so in this case -3 would be the y_{2} because it's the y in the ordered pair and it's the second one. Then one of the 5's would be x_{2} and 9 would be y_{1} and then the other 5 would be x_{1}.

now if we plug it in

\frac{-3-9}{5-5} =\frac{-12}{0}

now we can tell that we can't divide by zero so the slope would be unidentified and that's it.

5 0
3 years ago
What is the slope of this line. Please see image below
Mariulka [41]

Answer:

-2

Step-by-step explanation:

I mean i use the slope formula m = (y_{2} - y_{1}) / (x_{2} - x_{1}) and you just plug in the values of the coordinates.  

3 0
3 years ago
Read 2 more answers
Subtract −7n+2 ​​from 2n−1 ​. What is the answer? A.−5n+1 B.9n−3 C.9n + 1 D.−9n+3
Ludmilka [50]
Make sure that the subtraction is set up in the correct order. We are subtracting -7+2 FROM 2n-1.

(2n-1) - (-7n+2)

Distribute the negative.

(2n-1) + (7n-2)

Combine like terms.

9n - 3

The answer is B.
3 0
3 years ago
Read 2 more answers
May 26- 1
Dafna11 [192]

Answer:

  neither exponential nor linear

Step-by-step explanation:

A linear relationship will show a common difference between adjacent value. Here, the first differences between the first three values are 5 and 33. They are not the same, so the relation is not linear.

__

An exponential relationship will show first differences that are continuously increasing or decreasing by increasing or decreasing amounts (respectively).

As we showed, the difference between May 28 and May 27 is 33. This is more than the previous difference. However, the difference between May 30 and May 31 is only 28, which is less than a previous difference.

The relation is not exponential.

__

A graph points up the non-linearity of the relation.

4 0
3 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
Paha777 [63]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

We know that,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

Using the trigonometric ratios, we get

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Hence, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

6 0
3 years ago
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