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3 years ago

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Find the two smallest even numbers whose sum is 51

2 answers:

DochEvi [55]3 years ago

7 0

Answer:

25 plus 26

hoped that helped

lianna [129]3 years ago

4 0

25+26=51
Making 26 and 26 the two smallest even numbers that have a sum of 51

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Express 80 as the product of its prime factors.<br> Write the prime factors in ascending order.

stepan [7]

Answer:

the answer of that is 16 x 5

Step-by-step explanation:

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2 years ago

What is 56.6 in nearest whole number please help me ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

muminat

To the nearest whole number would be 57, because .6 rounds up to the next whole number

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3 years ago

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2 years ago

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Just answer number 7 and 8

melamori03 [73]

We are given the equation:
F = 2.25+0.2(m-1)
where:
F is the fare
m is the number of miles.

In question 7, we are given that the fare (F) is equal to $6.05 and we need to get the number of miles. To do so, we will simply substitute with the fare in the given equation and solve for the number of miles (m) as follows:
F = 2.25 + 0.2(m-1)
6.05 = 2.25 + 0.2(m-1)
6.05-2.25 = 0.2(m-1)
3.8 = 0.2(m-1)
3.8/0.2 = m-1
19 = m-1
m = 19+1
m = 20 miles

Number 8 is exactly the same, but we will substitute F=7.65 and again solve for m

4 0

3 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

<u><em>Interest compounded annually</em></u>

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

3 years ago