<span>t = 0.61 or 8.79
The equation you're giving is very badly formatted, but it looks like a variant of h = 47T - 1/2 AT^2 with the 1/2 already factored out and using an A of 10 m/s^2 which is close enough to the actual value of 9.8m/s^2. So I'll use the equation of h = 47t - 5t^2.
You're looking for a height of 27 meters. So let's assign that value:
h = 47t - 5t^2
27 = 47t - 5t^2
And we can manipulate that to make a quadratic equation. So:
27 = 47t - 5t^2
0 = 47t - 5t^2 - 27
-5t^2 + 47t - 27 = 0
Using the quadratic formula, we can find the roots at 0.61466 and 8.78534
So the rocket is at 27 meters at t = 0.61 seconds as it's going up and at t = 8.79 seconds as it's going back down.... Assuming of course, you don't have a parachute.</span>
Answer:
28 units²
Step-by-step explanation:
→ Work out the size of the triangle if it was a full rectangle
Height = 4 and Base = 2
→ Work out area of triangle
0.5 × Height × Base ⇒ 0.5 × 4 × 2 ⇒ 2 × 2 ⇒ 4
→ Minus the area of the triangle from the "imaginary full' rectangle
Area of rectangle = Length × Width ⇒ 8 × 4 ⇒ 32
32 - 4 = 28
Answer:
<h2> Y=3 but V=??????????????!!</h2>
The greatest common factor is the biggest number that divides evenly into each one of the numbers without a remainder...the only thing that's different about our situation is that we have variables in addition to regular number (but the same logic applies...we need to find the biggest variable that goes into k^4 , k^3 , and k^2 ).
The biggest number that goes into 15, 35 and 20 is the number 5. The biggest variable that goes into k^4 , k^3 , and k^2 is k^2
Combining the number and the variable, we get that the greatest common monomial factor is 5k^2
Since area is length x width, and we just figured out that width is 5k2 , all we have to do to find length is divide 15k4+35k3+20k2 by 5k2 , and we get that the length is 3k^2+7k+4
So the width is 5k^2 and the length is 3k2+7k+4
:))
-Eli
